1 / 20

Acids and Bases

Acids and Bases. Unit VII. I Electrolytes. An electrolyte is a compound, that when dissolved in water, conducts electricity How? Ions (charges) produced are free to move Movement of charge is conductivity Examples Acids Bases “Salts” Soluble Ionic compounds. II Properties. Acids

abbot-floyd
Download Presentation

Acids and Bases

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Acids and Bases Unit VII

  2. I Electrolytes • An electrolyte is a compound, that when dissolved in water, conducts electricity • How? • Ions (charges) produced are free to move • Movement of charge is conductivity • Examples • Acids • Bases • “Salts” • Soluble Ionic compounds

  3. II Properties • Acids • Good conductors • Dissolve metals • Table J--Metals above “H2” dissolve in acid • Taste sour • Turns litmus paper red • Turns phenolphthalein clear

  4. II Properties • Bases • Good conductors • Dissolve fats • Feels slippery • Taste bitter • Turns litmus paper blue • Turns phenolphthalein pink

  5. III Definitions • Arrhenius • Acids • An Arrhenius acid contains H+ ions • When dissolved in water these H+ ions combine to form hydronium ion (H3O+) • Examples: HCl H2SO4 HC2H3O2 • Bases • An Arrhenius base contains OH- ions (hydroxide ion) bonded to NH4+ or a metal • Examples: NaOHCa(OH)2

  6. III Definitions B. Brönsted-Lowry • Acids • A Brönsted-Lowry acid loses or donates protons to its conjugate (substance that differs by an H+) • HCl + NH3→Cl- + NH4+ • HCl and Cl- are conjugate pairs; HCl is the acid and Cl- is its conjugate base • Bases • A Brönsted-Lowry base gains or accepts protons from its conjugate • HCl + NH3→Cl- + NH4+ • NH3 and NH4+ are conjugate pairs; NH3 is the base and NH4+ is its conjugate acid

  7. IV Nomenclature A. Naming Compounds • Binary Acids • A binary acid contains hydrogen and a nonmetal • To name a binary acid • Use “hydro-” • Add nonmetal root word • End with “ic acid” • Ex. HCl • Hydrochloric acid • Ex. H2O • Hydroxic acid

  8. IV Nomenclature • Ternary Acids • A ternary acid contains hydrogen and a polyatomic ion • To name a ternary acid • Determine the polyatomic that is present using Reference Table E • If the polyatomic ion ends in “ate” change the ending to “ic” • If the polyatomic ion ends in “ite” change the ending to “ous” • Ex. HClO3 • Chlorate becomes Chloric acid (no hydro is used) • Ex. HNO2 • Nitrite becomes Nitrous acid

  9. IV Nomenclature • Bases • To name a base, name as you would any compound • Write the first element • Write the polyatomic • Add a Roman numeral if needed • Ex. NaOH • Sodium hydroxide • Ex. Cu(OH) 2 • Copper II hydroxide

  10. IV Nomenclature • Writing Formulas - Acids • If binary • Write H+ and the other element present • Assign charges and criss-cross • Ex. Hydrochloric acid H+1 Cl-1 HCl

  11. IV Nomenclature • If ternary • Identify the polyatomic present using ending • Write H+ and the polyatomic ion • Assign charges and criss-cross • Ex. Chloric acid • chloric comes from chlorate ClO3-1 • H+1 ClO3-1 • HClO3

  12. V Reactions A Neutralization • Mixing of acid and base • HCl + NaOH → • Makes salt and water • Break (ionize) the acid and base • H+1 Cl-1 Na +1 OH-1 • Join H to OH (H2O) • Join metal to nonmetal (assign charges and crisscross) • HCl + NaOH → H2O + NaCl

  13. Lab technique for neutralization is called Titration • Occurs when moles of acid equals moles of base • For 1:1 acid–base reactions • Moles acid = Moles base • MAVA = MBVB

  14. Examples of titration problems Given the balanced equation: HCl + NaOH → H2O + NaCl How many milliliters of 3.0M NaOH are needed to neutralize 20 milliliters of 2.5M HCl? • MB= 3.0M NaOH • MA= 2.5M HCl • VA= 20 mLsHCl • Ratio is 1:1 so MAVA = MBVB can be used • 2.5M x 20 mLs = 3.0M x VB • 50 = 3VB • VB=16.7 mLsNaOH

  15. Examples of titration problems Given the balanced equation: H2SO4 + 2 NaOH → 2 H2O + Na2SO4 How many milliliters of 1.2 M NaOH are needed to neutralize 23 milliliters of 1.9 M H2SO4? • MB= 1.2 M NaOH • MA= 1.9 M H2SO4 • VA= 23 mLs H2SO4 • Ratio is NOT 1:1 so MAVA = MBVB CANNOT be used 23mL H2SO4 x 1L x 1.9 mole H2SO4 x 2 mole NaOH x 1L x 1000 ml 1000 mL 1 L 1 mole H2SO4 1.2 mole NaOH 1L VB= 72.8 mLs NaOH

  16. IV Reactions B Hydrolysis • Mixing of salt and water • Makes parent acid and base of the salt NaCl + HOH → HCl + NaOH • Reverse of neutralization

  17. VI Strength • Acid and base strength depend on number of ions in solution • More ions; stronger acid or base • Some acids ionize 100% (strongest acids) • HCl HBr HI • H2SO4 HNO3 HClO4 • Some bases ionize 100% (strongest bases) • LiOH NaOH KOH • RbOH CsOH NH4OH

  18. pH Every aqueous solution contains H + and OH- • Acids have more H+ than OH- • Bases have more OH- than H+ pH represents the amount of H + in a solution 1 7 14 Strong Weak Neutral Weak Strong acid acid base base Most H+ Equal H+ and OH- Least H+ Least OH- Most OH-

  19. pH Scale is logarithmic • Values change by factors of 10 • ex. pH = 3 vs. pH = 5 • Difference in pH • 2 units • 10 x 10 • pH 3 is 100 times stronger than pH 5 • pH 5 is 1/100th as strong as pH 3

  20. Acid Base Indicators • Compounds that change color over pH ranges • Table M Common Acid–Base Indicators • methyl orange 3.2–4.4 red to yellow • bromthymol blue 6.0–7.6 yellow to blue • phenolphthalein 8.2–10 colorless to pink • litmus 5.5–8.2 red to blue • bromcresol green 3.8–5.4 yellow to blue • thymol blue 8.0–9.6 yellow to blue

More Related