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Warm Up

Warm Up. Problem of the Day. Lesson Presentation. Lesson Quizzes. Warm Up Solve. 1. x + 5 = 9 2. x – 34 = 72 3. 124 = x – 39. x = 4. x = 106. x = 163. Problem of the Day What 4-digit number am I? • I am greater than 4,000 and less than 5,000.

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Warm Up

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  1. Warm Up Problem of the Day Lesson Presentation Lesson Quizzes

  2. Warm Up Solve. 1.x + 5 = 9 2.x – 34 = 72 3. 124 = x – 39 x = 4 x = 106 x = 163

  3. Problem of the Day What 4-digit number am I? • I am greater than 4,000 and less than 5,000. • The sum of my hundreds digit and my ones digit is 9. • Twice my tens number is 2 more than my thousands digit. • The product of my hundreds digit and my ones digit is 0. • I am not an even number. 4,039

  4. Sunshine State Standards MA.7.A.3.4 Use the properties of equality to represent an equation in a different way and to show that two different equations are equivalent in a given context. Also MA.7.A.3.3

  5. Vocabulary Multiplication Property of Equality Division Property of Equality

  6. Like addition and subtraction, multiplication and division are inverse operations. They “undo” each other. 2 10 5 • = 2 5 10 ÷ =

  7. If a variable is divided by a number, you can often use multiplication to isolate the variable. Multiply both sides of the equation by the number.

  8. 26 ? = 13 2 ? 13 = 13 Additional Example 1: Using the Division Property of Equality h 2 Solve the equation = 13. Check your answer. h 2 = 13 h 2 Think: h is divided by 2, so multiply both sides by 2 to isolate h. (2) = 13(2) h = 26 Check h 2 = 13 Substitute 26 for h. 26 is a solution. 

  9. 150 ? = 30 5 ? 30 = 30 Check It Out: Example 1 x 5 Solve the equation = 30. Check your answer. x 5 = 30 x 5 Think: x is divided by 5, so multiply both sides by 5 to isolate x. (5) = 30(5) x = 150 Check x 5 = 30 Substitute 150 for x. 150 is a solution. 

  10. If a variable is multiplied by a number, you can often use division to isolate the variable. Divide both sides of the equation by the number.

  11. ? 51 = 17(3) ? 51 = 51 Additional Example 2: Solving an Equation by Division Solve the equation 51 = 17x. Check your answer. Think: x is multiplied by 17, so divide both sides by 17 to isolate x. 51 = 17x 51 = 17x 17 17 3 = x Check 51 = 17x Substitute 3 for x. 3 is a solution. 

  12. ? 76 = 19(4) ? 76 = 76 Check It Out: Example 2 Solve the equation 76 = 19y. Check your answer. Think: y is multiplied by 19, so divide both sides by 19 to isolate y. 76 = 19y 76 = 19y 19 19 4 = y Check 76 = 19y Substitute 4 for y. 4 is a solution. 

  13. Additional Example 3: Health Application Trevor’s heart rate is 78 beats per minute. How many times does his heart beat in 10 seconds? Use the given information to write an equation, where b is the number of heart beats in 10 seconds. If you count your heart beats for 10 seconds and then multiply that by 6, you can find your heart rate in beats per minute.

  14. Additional Example 3 Continued Beats in 10s times 6 = beats per minutes b · 6 = 78 Think: b is multiplied by 6, so divide both sides by 6 to isolate b. 6b = 78 6b = 78 6 6 b = 13 Trevor’s heart beats 13 times 10 seconds.

  15. Check It Out: Example 3 During a stock car race, one driver is able to complete 68 laps in 1 hour. How many laps would he finish in 15 minutes? Use the given information to write an equation, where n is the number of laps completed in 15 minutes. If you count the number of laps in 15 minutes and multiply by 4, you can find the number of laps completed in 1 hour.

  16. Check It Out: Example 3 Continued Laps in 15 min times 4 = Laps in 1 hour n · 4 = 68 4n = 68 Think: L is multiplied by 4, so divide both sides by 4 to isolate n. 4n = 68 4 4 n = 17 The driver would complete 17 laps in 15 minutes.

  17. Lesson Quizzes Standard Lesson Quiz Lesson Quiz for Student Response Systems

  18. x 4 x = 48; 12 = 198 22 h = 198; = 9 Lesson Quiz: Part I Solve the equation. Check your answer. 1. 12 = 4x 2. 18z = 90 3. 12 = 4. 840 = 12y 5. x = 3; 12 = 4  3 z = 5; 18  5 = 90 x 4 y = 70; 840 = 12  70 h 22 = 9

  19. Lesson Quiz: Part II 6. The cost of each ticket at the carnival was $0.25. Li bought $7.50 worth of tickets. How many tickets did she buy? 30

  20. Lesson Quiz for Student Response Systems 1. Solve the equation. Check your answer. 15 = A. x = ; = 3 C.x = 18; 15 + 3 = 18 B.x = 5; = 5 D.x = 45; 15 = x3 15 5 1 5 15 3 45 3

  21. Lesson Quiz for Student Response Systems 2. Solve the equation. Check your answer. = 7 A. f = ; 21 = 7 • 3 C.f = 28; 28 = 7 • 4 B.f = 3; = 7 D.f = 147; = 7 f21 1 3 21 3 147 21

  22. Lesson Quiz for Student Response Systems 3. Solve the equation. Check your answer. 45 = 9x A.x = 3; 45 = 3 • 15 B.x = 5; 45 = 9 • 5 C.x = 9; 45 = 5 • 9 D.x = 15; 45 = 15 • 3

  23. Lesson Quiz for Student Response Systems 4. Solve the equation. Check your answer. 12z = 72 A.z = 2; 2 • 36 = 72 B.z = 3; 3 • 24 = 72 C.z = 4; 4 • 18 = 72 D.z = 6; 12 • 6 = 72

  24. Lesson Quiz for Student Response Systems 5. The cost of one pen is $0.75. Joe bought $9.75 worth of pens. How many pens did he buy? A. 12 pens B. 13 pens C. 14 pens D. 15 pens

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