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Stable Isotope Ecology - RNEW 5500 Wednesday, September 3, 2008

Stable Isotope Ecology - RNEW 5500 Wednesday, September 3, 2008. Kinetic fractionation Rayleigh distillation Isotopic Mixing. reactant product. Non-equilibrium (kinetic) fractionation.

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Stable Isotope Ecology - RNEW 5500 Wednesday, September 3, 2008

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  1. Stable Isotope Ecology - RNEW 5500 Wednesday, September 3, 2008 Kinetic fractionation Rayleigh distillation Isotopic Mixing

  2. reactantproduct Non-equilibrium (kinetic) fractionation Forward reaction rate is accelerated relative to backward reaction and opportunity for backward mixing diminishes Change in temperature Product removal Most biological (enzyme) reactions

  3. Non-equilibrium (kinetic) fractionation Unidirectional reactions (e.g., enzyme reactions) Ratio of reaction rate constants (k) determine fractionation where k1 and k2 are reaction rate constants for the light and heavy isotopes, respectively

  4. Diffusive fractionation (a type of non-equilibrium or “kinetic” fractionation) During diffusion into a vacuum, a is the ratio of the velocities of the two isotopes, which is related to their masses:

  5. Isotope fractionation and Rayleigh distillation (sometimes called Rayleigh fractionation)

  6. Rayleigh fractionation/distillation Rayleigh fractionation occurs when a substrate mass is depleted during a physicochemical reaction and product is removed from system. The equation describing Rayleigh processes is: Rt = R0f (1-a) R and R0 are the ratios at t and at t=0 f is the fraction remaining at t ais the equilibrium fractionation factor Condensation example - condensate is fromed from a vapor mass and fraction remaining of original vapor declines

  7. Evaporation example - vapor is formed from the liquid and the fraction remaining of original liquid declines, as in an evaporating lake Rayleigh fractionation describes the process of ISOTOPE FRACTIONATION as a liquid pool evaporates (e.g., ephemeral pond) or as a vapor mass condenses (e.g., rainfall) Rayleigh fractionation creates differences in d values between source and product masses (e.g., liquid and vapor)

  8. As Rayleigh fractionation proceeds during evaporation, the d value of the accumulated vapor mass and the remaining water change. The pattern is dependent on whether you have a “CLOSED” or an “OPEN” system. The term “Rayleigh fractionation” is typically applied to the case of the OPEN system, not the closed-system (or “batch”) isotopic fractionation process. Evaporation example

  9. A =d18O of water ina CLOSED system B = d18O of vapor in a CLOSED system” A B In a CLOSED system, the vapor pool is in continuous contact with the liquid pool, and: dL = [adtot + 1000f(a-1)]/[a(1-f)+f] where f is residual water fraction, dtot is the d value of the total water, and a is the equilibrium fractionation between liquid and vapor. Evaporation example

  10. e e e As distillation proceeds in a CLOSEDsystem the two pools remain in contact, thus the liquid and vapor d values always differ by e owing to equilibration based on the fractionation factor (a)

  11. A B C In an OPEN system, instantaneous vapor is in equilibrium with the water but this vapor fraction is removed soon after formation and accumulates (cumulative vapor) elsewhere: Rt = R0f (1-a) R and R0 are the ratios at t and at t=0,f is the fraction remaining at t and ais the equilibrium fractionation factor. In delta notation: dL = (1000 + d0)f(a-1) - 1000 Evaporation example A = remaining water in OPEN system (liquid) B = instantaneous vapor in OPEN system C = accumulated vapor fraction being removed from the OPEN system

  12. A   B   C Evaporation example In an OPEN system, the remaining liquid (A) always differs from the instantaneous vapor (B) by the equilibrium enrichment value (e), but the accumulated vapor (C) becomes progressively more different from the remaining liquid.

  13. For all systems, if distillation is complete, the accumulated vapor mass must have a d value equal to the initial water mass Evaporation example

  14. Isotope mixing Linear mixing two isotope mixtures are related by: dsample = X dA + (1-X) dB IF the concentrations of the mixed phase are equal in each reservoir. (e.g., mixing waters with two differentd18O or d2H values). This works because16O ≈ 1 and H ≈ 1.0 (i.e., 16O >> 18O, H >> D). Concentration dependent mixing dsample = (CAmAdA + CB mBdB) / (CAmA + CBmB) This applies if the concentrations are different in the reservoirs such as mixing of sulfate pollution between two different waters.

  15. Fractional mixing when concentrations differ

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