1 / 67

CHAPTER 7

CHAPTER 7. QUADRATIC EQUATIONS AND FUNCTIONS. 7-1. Completing the Square. Completing the Square. Transform the equation so that the constant term c is alone on the right side. If a , the coefficient of the second-degree term, is not equal to 1, then divide both sides by a .

Download Presentation

CHAPTER 7

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. CHAPTER 7 QUADRATIC EQUATIONS AND FUNCTIONS

  2. 7-1 Completing the Square

  3. Completing the Square • Transform the equation so that the constant term cis alone on the right side. • If a, the coefficient of the second-degree term, is not equal to 1, then divide both sides by a. • Add the square of half the coefficient of the first-degree term, (b/2a)2, to both sides (Completing the square)

  4. Completing the Square • Factor the left side as the square of a binomial. • Complete the solution using the fact that (x + q)2 = r is equivalent to • x + q = ±r

  5. Solve: a2 – 5a + 3= 0 • Move the 3 to the other side • a = 1 • Complete the square, add (5/2)2 • Factor • Solve

  6. Solve: x2 – 6x - 3= 0 • Move the 3 to the other side • a = 1 • Complete the square, add (3)2 • Factor • Solve

  7. Solve: 2y2 + 2y + 5 = 0 • move the 5 to the other side • divide both sides by 2 (a  1) • Add (1/2)2 to both sides • Factor • Solve

  8. Solve: 7x2 – 8x + 3 = 0 • move the 3 to the other side • divide both sides by 7 (a  1) • Add (4/7)2 to both sides • Factor • Solve

  9. 7-2 Quadratic Formula

  10. The Quadratic Formula The solutions of the quadratic equation ax2 + bx + c = 0 (a  0) are given by the formula:

  11. Solve • 3x2 + x – 1 = 0 • 5y2 = 6y – 3 • 2x2 – 3x + 7 = 0

  12. 7-3 The Discriminant

  13. Discriminant The discriminant is used to determine the nature of the roots of a quadratic equation and is equal to: D = b2 – 4ac

  14. Discriminant Cases • If D is positive, then the roots are real and unequal. • If D is zero, then the roots are real and equal (double root) . • negative, the roots are imaginary.

  15. Find the Discriminant • x2 + 6x – 2 = 0 • 3x2 – 4x√3 + 4 = 0 • x2 – 6x + 10 = 0

  16. Discriminant The discriminant also show you whether a quadratic equation with integral coefficients has rational roots. D = b2 – 4ac

  17. Test for Rational Roots • If a quadratic equation has integral coefficients and its discriminant is a perfect square, then the equation has rational roots.

  18. Test for Rational Roots • If the quadratic equation can be transformed into an equivalent equation that meets this test, then it has rational roots.

  19. Find the Determinant and Identify the Nature of the Roots • 3x2 - 7x + 5 = 0 • 2x2 - 13x + 15 = 0 • x2 + 6x + 10 = 0

  20. 7-4 Equations in Quadratic Form

  21. Quadratic Form An equation in quadratic form can be written as: a[f(x)]2 + b[(f(x)] + c = 0 where a 0 and f(x) is some function of x. It is helpful to replace f(x) with a single variable.

  22. Example (3x – 2)2 – 5(3x -2) – 6 = 0 Let z = 3x – 2, then z2 – 5z – 6 = 0 Solve for z and then solve for x

  23. Solve Using Quadratic Form • (x + 2)2 – 5(x + 2) – 14 = 0 • (3x + 4)2 + 6(3x + 4) – 16 = 0 • x4 + 7x2 – 18 = 0

  24. 7-5 Graphing y – k = a(x- h)2

  25. Parabola Parabola is the set of all points in the plane equidistant from a given line and a given point not on the line. Parabolas have an axis of symmetry (mirror image) either the x-axis or the y-axis. and

  26. Parabola The point where the parabola crosses it axis is the vertex.The graph is a smooth curve.

  27. Parabola The graph of an equation having the form y – k = a(x - h)2 has a vertex at (h, k) and its axis is the line x = h.

  28. Graph • y = x2 Use the form y – k = a(x – h)2 k= 0, h = 0, so the vertex is (0,0) and x = 0

  29. Table of Values

  30. Graph • y = ½x2 Use the form y – k = a(x – h)2 k= 0, h = 0, so the vertex is (0,0) and x = 0

  31. Graph • y = -½x2 Use the form y – k = a(x – h)2 k= 0, h = 0, so the vertex is (0,0) and x = 0

  32. Graph • The graph of y = ax2 opens upward if a> 0 and downward if a< 0. The larger the absolute value of a is, the “narrower” the graph.

  33. Graph • y = ½(x-3)2 Use the form y – k = a(x – h)2 k= 0, h = 3, so the vertex is (3,0) and x = 3

  34. Graph • To graph y = a(x – h)2, slide the graph of y = ax2 horizontally h units. If h > 0, slide it to the right; if h < 0, slide it to the left. The graph has vertex (h, 0) and its axis is the line x = h.

  35. Graph • y – 3 = ½x2 Use the form y – k = a(x – h)2 k= 3, h = 0, so the vertex is (0,3) and x = 0

  36. Graph • y + 3 = ½x2 Use the form y – k = a(x – h)2 k= -3, h = 0, so the vertex is (0,-3) and x = 0

  37. Graph • To graph y – k = ax2, slide the graph of y = ax2 vertically k units. If k > 0, slide it upward; if k < 0, slide it downward. The graph has vertex (0, k) and its axis is the line x = 0.

  38. 7-6 Quadratic Functions

  39. Quadratic Functions A function that can be written in either of two forms. General form: f(x) = ax2 + bx + c Completed square form: a(x-h)2 + k

  40. Graph • f(x) = 2(x – 3)2 + 1 y = 2(x – 3)2 + 1

  41. Graph • It’s a parabola with vertex (3,1) and axis x = 3

More Related