1 / 8

1.8 Perimeter Word Problems

1.8 Perimeter Word Problems. Today’s Date: 9/8/11. Notes on Handout. Perimeter. Rectangle:. l. w. w. Perimeter = l + l + w + w = 2 l + 2 w. l. Triangle:. a. b. Perimeter = a + b + c. c. Word Problems. The perimeter of a triangle “ is ” 72. “ is ” means =.

kent
Download Presentation

1.8 Perimeter Word Problems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 1.8 Perimeter Word Problems Today’s Date: 9/8/11 Notes on Handout

  2. Perimeter Rectangle: l w w Perimeter = l + l + w + w = 2l + 2w l Triangle: a b Perimeter = a + b + c c

  3. Word Problems The perimeter of a triangle “is” 72. “is” means = a + b + c = 72 A length is 3 less “than” the width. “than” means switch the order l = w – 3 with subtraction, order matters l = 3 – w WRONG!!

  4. Word Problems On the TEST: a) Define the variable b) Write the equation c) Solve W = width L = length 2(w + 5) + 2w = 170 width = 40 feet length = 45 feet

  5. Examplesa) Define variable b) Write eqtn. c) Solve 1) The length of a rectangle is 5 inches more than the width. The perimeter is 34 inches. Find the length and width. l = w + 5 l= (w + 5) a) l = length w = width = 34 2l + 2w 2l+ 2w b) 2(w + 5) + 2w = 34 2w + 10 + 2w = 34 4w + 10 = 34 4w = 24 w = 6 • width = 6 in. • length = 11 in. = 11 l = 6 + 5

  6. Examples a) Define variable b) Write eqtn. c) Solve 2) The length of a rectangle is 5 inches more than twice the width. The perimeter is 34 inches. Find the length and width. l= (2w + 5) l = 2w + 5 a) l = length w = width = 34 2l + 2w 2l+ 2w b) 2(2w + 5) + 2w = 34 4w + 10 + 2w = 34 6w + 10 = 34 6w = 24 w = 4 • width = 4 in. • length = 13 in. l = 2(4) + 5 = 8 + 5 = 13

  7. Examplesa) Define variable b) Write eqtn. c) Solve 2nd side 3) One side of a triangle is twice the shortest side. The third side is 3 feet more than the shortest side. The perimeter is 19 feet. Find all three sides. b = 2a b = 2a • a = shortest side • b = 2nd side • c = 3rd side c = a + 3 c = a + 3 a + b + c = 19 a + b + c = 19 c) 1st side = 4 ft. 2nd side = 8 ft. 3rd side = 7 ft. b) a + 2a + a + 3 = 19 4a + 3 = 19 4a = 16 a = 4 b a b = 2(4) = 8 c c = 4 + 3 = 7

  8. Homework #6 “Ant” Worksheet **Do on a Separate Paper** Show all work for a stamp!

More Related