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calorie s pecific heat capacity

vocab word--the quantity of heat needed to raise the temperature of 1 g of water 1°C 2) vocab word--the amount of energy required to raise the temperature of 1 g of a substance 1°C. calorie s pecific heat capacity.

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calorie s pecific heat capacity

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  1. vocab word--the quantity of heat needed to raise the temperature of 1 g of water 1°C2) vocab word--the amount of energy required to raise the temperature of 1 g of a substance 1°C • calorie • specific heat capacity

  2. vocab word--the amount of energy required to raise the temperature of 1 mol of a substance 1°C2) vocab word--the study of heat changes that accompany chemical reactions • molar heat capacity • thermochemistry

  3. vocab word--a food calorie2) vocab word--the SI unit of heat3) vocab word--chemical reactions that include a heat term • Calorie • Joule • thermochemical equation

  4. vocab word--a device used to measure the amount of heat absorbed or released during chemical or physical process2) vocab word--the accurate and precise measurement of heat change for chemical and physical processes • calorimeter • calorimetry

  5. vocab word--measurement of heat when using constant-pressure calorimetry2) vocab word--form of energy that always flows from a warmer object to a cooler object • enthalpy • heat

  6. vocab word—process that absorbs or gains heat from the surroundings2) vocab word—the ability or capacity to do work • endothermic • energy

  7. vocab word– the heat change caused by the dissolution of one mole of a substance2) vocab word—the change in enthalpy that accompanies the formation of 1 mole of a compound from its elements • Molar heat of solution • Standard heat of formation

  8. vocab word—the heat absorbed by 1 mole of a substance in melting from a solid to a liquid2) vocab word—the amount of heat necessary to vaporize 1 mole of a given liquid • Molar heat of fusion • Molar heat of vaporization

  9. vocab word—process that releases or loses heat to the surroundings2) vocab word—states that if you add two or more thermochemical equations to give a final equation, then you can add the heats of reaction to give the final heat of reaction • exothermic • Hess’s Law

  10. Endothermic or Exothermic? exothermic

  11. Endothermic or Exothermic? endothermic

  12. Endothermic or Exothermic? exothermic

  13. Endothermic or Exothermic? endothermic

  14. Endothermic or Exothermic? endothermic

  15. Endothermic or Exothermic? exothermic

  16. Endothermic or Exothermic? exothermic

  17. Endothermic or Exothermic? endothermic

  18. Endothermic or Exothermic endothermic

  19. Endothermic or Exothermic? exothermic

  20. Endothermic or Exothermic? 4 NO(g) + 6 H2O(l) → 4 NH3(g) + 5 O2(g) ΔH = +1170 kJ endothermic NH3(g) + HCl(g) → NH4Cl(s) ΔH = −176 kJ exothermic

  21. Endothermic or Exothermic? H2(g) + ½ O2(g) → H2O(g) + 286 kJ exothermic HgO (s) + 90.7 kJ → Hg (l) + ½ O2 (g) endothermic

  22. A certain mass of water was heated with 41,840 Joules, raising its temperature from 22.0 °Cto 28.5 °C. Find the mass of water. The specific heat of water is 4.184 J/(g·C°). 41840 J = m x 6.5C x 4.184 J/g C m = 1538 g

  23. If it takes 41.72 joules to heat a piece of gold weighing 18.69 g from 10.0 °C to 27.0 °C, what isthe specific heat of the gold? 41.72 J = 18.69 g x 17C x C C = 0.131 J/(g·C°)

  24. Given that the specific heat capacity of gold is 0.131 J/(g·C°), find its molar heat capacity.

  25. The temperature of 110 mL of water rises from 25.0°C to 26.2°C when 0.10 mol of H+ is reacted with 0.10 mol of OH-. Calculate the amount of heat released. Assume that the denisty of the solution is 1.00 g/mL. The specific heat of water is 4.184 J/(g·C°).

  26. How much heat energy is obtained when 1 kg of ethane gas, C2H6, is burned in oxygen according to the equation:2C2H6(g) + 7O2(g) → 4CO2(g) + 6H2O(l); ΔH = –3120 kJ

  27. Determine the energy required to boil 43.89 grams of water at 100.0 °C. The ∆Hvapor of H2O is 40.67 kJ/mol.

  28. What is the value for ΔH for the following reaction?CS2(l) + 3 O2(g) → CO2(g) + 2 SO2(g) Given:C(s) + O2(g) → CO2(g); ΔH= -393.5 kJS(s) + O2(g) → SO2(g); ΔH= -296.8 kJC(s) + 2 S(s) → CS2(l); ΔH= 87.9 kJ Hess’s Law, double 2ndrxn, reverse 3rdrxn H = -1075 kJ

  29. CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)∆H° = –889.1 kJ∆Hf° H2O(l) = –285.8 kJ/mol∆Hf° CO2(g) = –393.3 kJ/molWhat is the standard heat of formation of methane, ∆Hf° of CH4(g), as calculated from the data above? −889.1 = [−393.3 + 2(−285.8)]−[x + 2(0)] x = ∆Hf° of CH4(g) = −75.8 kJ/mol

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