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Program Verification as Probabilistic Inference

Program Verification as Probabilistic Inference. Sumit Gulwani Nebojsa Jojic Microsoft Research, Redmond. Problem of Program Verification. Given a program with a pre/post-condition pair, discover proof of validity or invalidity.

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Program Verification as Probabilistic Inference

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  1. Program Verification as Probabilistic Inference Sumit Gulwani Nebojsa Jojic Microsoft Research, Redmond

  2. Problem of Program Verification • Given a program with a pre/post-condition pair, discover proof of validity or invalidity. • Proof is in the form of an invariant at each program point that can be locally verified.

  3. Example 1 x = 0 Proof of Validity entry y := 50; 1 2 x <100 False True exit 3 y = 100 x < 50 True False 6 4 x := x +1; y := y +1; x := x +1; 5 7 8

  4. Machine Learning Algorithm for Program Verification • Initialize invariants at all program points to any element (from an abstract domain over which the proof exists) • Pick a program point (randomly) whose invariant is locally inconsistent & update it to make it less inconsistent.

  5. Outline • Inconsistency Measure • Algorithm • Experiments

  6. Consistency of an invariant I at program point  I is consistent at  iff Post() ) I Æ I ) Pre() • Post() is the strongest postcondition of “the invariants at the predecessors of ” at  • Pre() is the weakest precondition of “the invariants at the successors of ” at  • Example: 1 P s 2 • Post(2) = StrongestPost(P,s) • Pre(2) = (c ) Q) Æ (: c ) R) I c 4 3 Q R

  7. Measuring Inconsistency of an invariant I at  Local inconsistency of invariant I at program point  = IM(Post(), I) + IM(I, Pre()) Where the inconsistency measure IM(1, 2) is some approximation of the number of program states that violate 1)2

  8. Example of an inconsistency measure IM Consider the abstract domain of Boolean formulas (with the usual implication as the partial order). Let 1´ a1Ç … Ç an in DNF and 2´ b1Æ … Æ bm in CNF IM(1, 2) = (ai,bj) where (ai,bj) = 0, if ai) bj = 1, otherwise

  9. Outline • Inconsistency Measure & Penalty Function • Algorithm • Experiments

  10. Algorithm • Search for proof of validity and invalidity in parallel. • Same algorithm with different boundary conditions. • Proof of Validity • Iexit = Postcondition • Ientry = Precondition • Proof of Invalidity • Iexit = : Postcondition • Ientry) Precondition, and Ientry is satisfiable • This assumes that program terminates on all inputs.

  11. Algorithm (Continued) • Initialize invariant Ij at program point j to any element (from an abstract domain over which the proof exists) • While invariant at some point is locally inconsistent: • Choose j randomly s.t. Ij is inconsistent at j • Update Ij s.t. inconsistency of Ij at j is minimized [Sandwich Step] • More precisely, Ij is chosen randomly with probability inversely proportional to its inconsistency at j (to avoid getting stuck in a local minima). But now, termination is only probabilistic.

  12. Comparison with Interpolants Interpolant Given 1, 2 such that 1)2, find  such that: • 1))2 • Vars() µ Vars(1) Å Vars(2) Sandwich Step Given 1, 2, find  such that: • IM(1, ) + IM(,2) is minimum (i.e., # of states violating 1))2 is minimum) •  is from a given abstract domain

  13. Intersection of Forward & Backward Analysis x = 0 y := 50; 1 2 x <100 False True • - Assume abstract elements can have at most 3 conjuncts. • Post(8): x¸0 Æx·100 Æ (x·50 Çx=y) Æ (y=50 Çx¸51). Dropping any conjunct is a valid choice at 8 in a forward analysis. • But backward guidance from 2 calls for keeping x·100 and (x·50 Çx=y) 3 y = 100 x < 50 True False 6 4 x := x +1; y := y +1; x := x +1; 5 7 8

  14. Outline • Inconsistency Measure & Penalty Function • Algorithm • Experiments

  15. Example 1 x = 0 Proof of Validity entry y := 50; 1 2 x <100 False True exit 3 y = 100 x < 50 True False 6 4 x := x +1; y := y +1; x := x +1; 5 7 8

  16. Stats: Proof vs Incremental Proof of Validity • Black: Proof of Validity • Grey: Incremental Proof of Validity • Incremental proof requires fewer updates

  17. Stats: Different Sizes of Boolean Formulas • Grey: 5*3, Black: 4*3, White: 3*2 • n*m denotes n conjuncts & m disjuncts • Larger size requires fewer updates

  18. * Example 2 true Proof of Validity entry x := 0; m := 0; 1 2 x < n False True exit 3 n· 0 Ç 0· m < n 4 6 m := x; 5 7 x := x +1; 8

  19. Stats: Proof of Validity • Example 2 is “easier” than Example 1. • Easier example requires fewer updates.

  20. Related Work: Probabilistic Techniques • Used successfully in several areas of computer science. • Yields more efficient, precise, even simpler algorithms. • An earlier technique: Random Interpretation [POPL ’03-’05] • Discovers program invariants • Monte Carlo Algorithm: May generate invalid invariants with a small probability. Running time is bounded. • “Random Testing” + “Abstract Interpretation” • This talk: Machine Learning • Discovers proof of validity/invalidity of a Hoare triple. • Las Vegas Algorithm: Generates a correct proof. Running time is probabilistic. • “Forward Analysis” + “Backward Analysis”

  21. Conclusion • Combining Randomized & Symbolic techniques is powerful • Interprocedural Random Interpretation [POPL ’05] • DART [PLDI ’05], Yogi [FSE ’06] • This work • Machine Learning Algorithm • Inconsistency Measure for an abstract domain: How far are two abstract elements from satisfying the partial order? • Algorithm: Pick a program point (randomly) whose invariant is locally inconsistent & update it to make it less inconsistent. • Intersection of forward and backward analysis.

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