1 / 11

Analysis of the phase shift error between A and B signals in BPMs

Analysis of the phase shift error between A and B signals in BPMs. BPM project. The phase shift problem. A phase shift between A and B signals may arise do to different time propagation delays of A and B in the front-end electronics. The propagation time in cables is ~1ns/ft.

terris
Download Presentation

Analysis of the phase shift error between A and B signals in BPMs

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Analysis of the phase shift error between A and B signals in BPMs BPM project Gustavo Cancelo

  2. The phase shift problem • A phase shift between A and B signals may arise do to different time propagation delays of A and B in the front-end electronics. • The propagation time in cables is ~1ns/ft. • A to B cable length mismatch of 1.5cm generates a phase shift of 1 degree. • A and B signals are individually processed by analog filters. Different relative phases in the analog filters will generate an A to B phase shift. Gustavo Cancelo

  3. A to B signal shift simulation • The phase of B is advanced with respect to the phase of A in steps of 2.57º (degrees) in the interval [0º,36º]. • The simulation computes the error in position calculation as a function of the phase shift. Gustavo Cancelo

  4. 1 A waveform 15 B waveforms A and shifted B plots at high sampling frequency 36º of total phase shift in 2.57º increments Gustavo Cancelo

  5. 1 A waveform 15 B waveforms Plots of A and shifted B, sampled at 74MHz Samples 36º of total phase shift in 2.57º increments Gustavo Cancelo

  6. Gustavo Cancelo

  7. Spectrum analysis Spectrum of A after down conversion Gustavo Cancelo

  8. Spectrum analysis This plot shows the spectrum of A, and B shifted by 36º. The frequency range has been zoomed to 300KHz. (300KHz is the bandwidth of the “envelope filter”) The red dots represent the B magnitude and the green dots the A magnitude. Gustavo Cancelo

  9. This plot shows the spectrum of A and B shifted by 36º. The frequency range has been around DC. The red dot represent the DC component of B and the green dots represent the DC component of A. Spectrum analysis ~ 0.2% Gustavo Cancelo

  10. Model of the shift problem Signal model: Fourier transforms: Ringing filter model for time and frequency domains: Signal at the output of the ringing filter (frequency domain) where where The shift shows as phase information Gustavo Cancelo

  11. Model of the shift problem Let’s assume that the signal is filtered using an ideal filter with a cutoff freq. = ω0 (e.g. ω0=2*π*300KHz) and unit gain. Gustavo Cancelo

More Related