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Speed and Velocity Page 1a Schaum's 1

Speed and Velocity Page 1a Schaum's 1. v = x/t x = vt. v = .25 m/s t = 4 min ( 60 sec/min) = 240 sec. x = .25 (240) x = 60 m. v = x/t. x = 10 km ( 1000m/km) = 10000 m t = 3 min ( 60 sec/min) = 180 sec. v = 10000/180 v = 55.56 m/s. v = x/t t = x/v. v = 4.25 m/s

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Speed and Velocity Page 1a Schaum's 1

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  1. Speed and Velocity Page 1a Schaum's 1 v = x/t x = vt v = .25 m/s t = 4 min ( 60 sec/min) = 240 sec x = .25 (240) x = 60 m v = x/t x = 10 km ( 1000m/km) = 10000 m t = 3 min ( 60 sec/min) = 180 sec v = 10000/180 v = 55.56 m/s v = x/t t = x/v v = 4.25 m/s x = 17 m t = 17/4.25 t = 4 sec 0.2 cm ( 1m ) ( 1km ) ( 3600sec ) ( 24 hrs ) ( 365 days ) = 63.07 km/yr sec (100cm) (1000m ) ( 1 hr ) ( 1 day ) ( 1 year ) 1.1 A toy train moves along a winding track at an average speed of 0.25 m/s. How far will it travel in 4 minutes? 1.2 A student driving a car travels 10 km in 30 min. What was her average speed? 1.3 Rolling across the machine shop at constant speed of 4.25 m/s, a robot covers a distance of 17m. How long did that journey take? 1.4 Change the speed of 0.200 cm/s to kilometers per year.

  2. b) displacement = 0 1 lap velocity = 0 v = x/t v = 200 / 25 v = 8 m/s a) x = 200 m t = 25 sec v = x/t x= 380 m t = 40 sec v = 380 / 40 v = 9.5 m/s x = 1200 m v = 20 m/s v = x/t t = x/v t = 1200 / 20 t = 60 seconds Speed and Velocity Page 1b Schaum's 1 1.7 A runner makes one lap around a 200 m track in a time of 25 s. What were the runner's a) average speed and b) average velocity? 1.18 Three kids in a parking lot launch a rocket that rises into the air along a 380 m long arc in 40 s. Determine the average speed. 1.19 According to its computer, a robot that left its closet and traveled 1200 m, had an average speed of 20 m/s. How long did the trip take?

  3. x1 = 22687 km x2 = 22791 km t = 4 hrs v = 22791 - 22687 26 km ( 1000m ) ( 1 hr ) hr ( 1 km) ( 3600 sec ) 4 v = Δx v = 7.26 m / sec v = 26 km / hr t v = x / t x = vt x1 = 25 km/hr ( 4 min ) ( 1 hr / 60 min) = 1.67 km x2 = 50 km/hr ( 8 min ) ( 1 hr / 60 min) = 6.67 km x1 = 20 km/hr ( 2 min ) ( 1 hr / 60 min) = 0.67 km Total distance = 1.67 + 6.67 + 0.67 = 9.01 km = 9010 m Total time = 4 + 8 + 2 = 14 min ( 60 sec / 1 min ) = 840 seconds Average speed = 9010 / 840 = 10.73 m/s Speed and Velocity Page 1c Schaum's 1 1.20 A car's odometer reads 22687 km at the start of a trip and 22791 km at end. The trip took 4 hours. What was the car's average speed in km/h and m/s? 1.21 An auto travels at the rate of 25 km/h for 4 minutes, then at 50 km/h for 8 minutes and finally at 20 km/h for 2 minutes. Find a) the total distance covered in km and b) the average speed for the trip in m/s.

  4. 40m c = 126 m = 1 lap Speed and Velocity Page 1d Schaum's 1 1.25 A runner travels 1.5 laps around a circular track in a time of 50 s. The diameter of the track is 40 m and its circumference is 126m. Find a) the average speed of the runner b) the magnitude of the runner's average velocity. b) average velocity displacement is 0.5 laps 0.5 laps is the diameter a) average speed distance is circumference (1.5 laps) ( 126 m / lap) = 189 m v = x / t v = 40 / 50 v = 0.8 m/s v = x / t v = 189 / 50 v = 3.78 m/s 1.26 During a race on an oval track, a car travels at an average speed of 200 km/h. a) How far did it travel in 45 min? b) Determine its average velocity at the end of its third lap. a) v = 200 km/hr t = 45 min ( 1 hr / 60 min) = 0.75 hrs b) displacement = 0 3 complete laps velocity = 0 v = x / t x = vt x = 200 ( .75 ) x = 150 km

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