1 / 30

RFSS: Lecture 2 Nuclear Properties

RFSS: Lecture 2 Nuclear Properties. Readings: Modern Nuclear Chemistry: Chapter 2 Nuclear Properties Nuclear and Radiochemistry: Chapter 1 Introduction, Chapter 2 Atomic Nuclei Nuclear properties Masses Binding energies Reaction energetics Q value Nuclei have shapes.

alaire
Download Presentation

RFSS: Lecture 2 Nuclear Properties

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. RFSS: Lecture 2Nuclear Properties • Readings: • Modern Nuclear Chemistry: Chapter 2 Nuclear Properties • Nuclear and Radiochemistry: Chapter 1 Introduction, Chapter 2 Atomic Nuclei • Nuclear properties • Masses • Binding energies • Reaction energetics • Q value • Nuclei have shapes

  2. Nuclear Properties • Systematic examination of measurable data to determine nuclear properties • masses • matter distributions • Size, shape, mass, and relative stability of nuclei follow patterns that can be understood and interpreted with models • average size and stability of a nucleus described by average nucleon binding in a macroscopic model • detailed energy levels and decay properties evaluated with a quantum mechanical or microscopic model Simple example: Number of stable nuclei based on neutron and proton number N even odd even odd Z even even odd odd Number 160 53 49 4 Simple property dictates nucleus behavior. Number of protons and neutron important

  3. Which are the 4 stable odd-odd nuclei?

  4. Data from Mass • Evaluation of Mass Excess • Difference between actual mass of nucleus and expected mass from atomic number • By definition 12C = 12 amu • If mass excess negative, then isotope has more binding energy the 12C • Mass excess==M-A • M is nuclear mass, A is mass number • Unit is MeV (energy) • Convert with E=mc2 • 24Na example • 23.990962782 amu • 23.990962782-24 = -0.009037218 amu • 1 amu = 931.5 MeV • -0.009037218 amu x (931.5 MeV/1 amu) • -8.41817 MeV= Mass excess= for 24Na

  5. Masses and Q value • Atomic masses • From nuclei and electrons • Nuclear mass can be found from atomic mass • m0 is electron rest mass, Be (Z) is the total binding energy of all the electrons • Be(Z) is small compared to total mass • Energy (Q) from mass difference between parent and daughter • Mass excess values can be used to find Q (in MeV) • β- decay Q value • AZA(Z+1)+ + β- +n + Q • Consider β- mass to be part of A(Z+1) atomic mass (neglect binding) • Q=DAZ-DA(Z+1) • 14C14N+ + β- +n + Q • Energy =Q= mass 14C – mass 14N • Use Q values (http://www.nndc.bnl.gov/wallet/wccurrent.html) • Q=3.0198-2.8634=0.156 MeV

  6. Q value • Positron Decay • AZA(Z-1)-+ β++n + Q • Have 2 extra electrons to consider • β+ (positron) and additional atomic electron from Z-1 daughter • Each electron mass is 0.511 MeV, 1.022 MeV total from the electrons • Q=DAZ – (DA(Z-1)- + 1.022)MeV • 90Nb90Zr-+ β++n + Q • Q=D 90Nb – (D 90Zr + 1.022) MeV • Q=-82.6632-(-88.7742+1.022) MeV=5.089 MeV • Electron Capture (EC) • Electron comes from parent orbital • Parent can be designated as cation to represent this behavior • AZ+ + e- A(Z-1)+ n + Q • Q=DAZ – DA(Z-1) • 207Bi207Pb +n + Q • Q=D 207Bi– D207Pb MeV • Q= -20.0553- -22.4527 MeV=2.3947 MeV

  7. Q value • Alpha Decay • AZ(A-4)(Z-2) + 4He + Q • 241Am237Np + 4He + Q • Use mass excess or Q value calculator to determine Q value • Q=D241Am-(D 237Np+D4He) • Q = 52.937-(44.874 + 2.425) • Q = 5.638 MeV • Alpha decay energy for 241Am is 5.48 and 5.44 MeV

  8. Q value determination • For a general reaction • Treat Energy (Q) as part of the equation • Solve for Q • 56Fe+4He59Co+1H+Q • Q= [M56Fe+M4He-(M59Co+M1H)]c2 • M represents mass of isotope • Q=-3.241 MeV (from Q value calculator) • Mass excess and Q value data can be found in a number of sources • Table of the Isotopes • Q value calculator • http://www.nndc.bnl.gov/qcalc/qcalcr.jsp • Atomic masses of isotopes • http://physics.nist.gov/cgi-bin/Compositions/stand_alone.pl

  9. Q value calculation examples • Find Q value for the Beta decay of 24Na • 24Na24Mg+ +b- + n +Q • Q= 24Na-24Mg • M (24Na)-M(24Mg) • 23.990962782-23.985041699 • 0.005921 amu • 5.5154 MeV • From mass excess • -8.417 - -13.933 • 5.516 MeV • Q value for the EC of 22Na • 22Na+ + e-22Ne + n +Q • Q= 22Na - 22Ne • M (22Na)-M(22Ne) • 21.994436425-21.991385113 • 0.003051 amu • 2.842297 MeV • From mass excess • -5.181 - -8.024 • 2.843 MeV

  10. Terms from Energy • Binding energy • Difference between mass of nucleus and constituent nucleons • Energy released if nucleons formed nucleus • Nuclear mass not equal to sum of constituent nucleons Btot(A,Z)=[ZM(1H)+(A-Z)M(n)-M(A,Z)]c2 • average binding energy per nucleon • Bave(A,Z)= Btot(A,Z)/A • Some mass converted into energy that binds nucleus • Measures relative stability • Binding Energy of an even-A nucleus is generally higher than adjacent odd-A nuclei • Exothermic fusion of H atoms to form He from very large binding energy of 4He • Energy released from fission of the heaviest nuclei is large • Nuclei near the middle of the periodic table have higher binding energies per nucleon • Maximum in the nuclear stability curve in the iron-nickel region (A~56 through 59) • Responsible for the abnormally high natural abundances of these elements • Elements up to Fe formed in stellar fusion

  11. Mass Based Energetics Calculations • Why does 235U undergo neutron induced fission for thermal energies while 238U doesn’t? • Generalized energy equation • AZ + n A+1Z + Q • For 235U • Q=(40.914+8.071)-42.441 • Q=6.544 MeV • For 238U • Q=(47.304+8.071)-50.569 • Q=4.806 MeV • For 233U • Q=(36.913+8.071)-38.141 • Q=6.843 MeV • Fission requires around 5-6 MeV • Does 233U from thermal neutron?

  12. Binding-Energy Calculation: Development of simple nuclear model • Volume of nuclei are nearly proportional to number of nucleons present • Nuclear matter is incompressible • Basis of equation for nuclear radius • Total binding energies of nuclei are nearly proportional to numbers of nucleons present • saturation character • Nucleon in a nucleus can apparently interact with only a small number of other nucleons • Those nucleons on the surface will have different interactions • Basis of liquid-drop model of nucleus • Considers number of neutrons and protons in nucleus and how they may arrange • Developed from mass data • http://en.wikipedia.org/wiki/Semi-empirical_mass_formula

  13. Liquid-Drop Binding Energy: • c1=15.677 MeV, c2=18.56 MeV, c3=0.717 MeV, c4=1.211 MeV, k=1.79 and =11/A1/2 • 1st Term: Volume Energy • dominant term • in first approximation, binding energy is proportional to the number of nucleons • (N-Z)2/A represents symmetry energy • binding E due to nuclear forces is greatest for the nucleus with equal numbers of neutrons and protons

  14. Liquid drop model • 2nd Term: Surface Energy • Nucleons at surface of nucleus have unsaturated forces • decreasing importance with increasing nuclear size • 3rd and 4th Terms: Coulomb Energy • 3rd term represents the electrostatic energy that arises from the Coulomb repulsion between the protons • lowers binding energy • 4th term represents correction term for charge distribution with diffuse boundary •  term: Pairing Energy • binding energies for a given A depend on whether N and Z are even or odd • even-even nuclei, where =11/A1/2, are the most stable • two like particles tend to complete an energy level by pairing opposite spins • Neutron and proton pairs

  15. Magic Numbers: Data comparison • Certain values of Z and N exhibit unusual stability • 2, 8, 20, 28, 50, 82, and 126 • Evidence from different data • masses, • binding energies, • elemental and isotopic abundances • Concept of closed shells in nuclei • Similar to electron closed shell • Demonstrates limitation in liquid drop model • Magic numbers demonstrated in shell model • Nuclear structure and model lectures

  16. Mass Parabolas • Method of demonstrating stability for given mass constructed from binding energy • Values given in difference, can use energy difference • For odd A there is only one -stable nuclide • nearest the minimum of the parabola Friedlander & Kennedy, p.47

  17. Even A mass parabola • For even A there are usually two or three possible -stable isobars • Stable nuclei tend to be even-even nuclei • Even number of protons, even number of neutron for these cases

  18. Nuclear Shapes: Radii • Nuclear volumes are nearly proportional to nuclear masses • nuclei have approximately same density • nuclei are not densely packed with nucleons • Density varies • ro~1.1 to 1.6 fm for equation above • Nuclear radii can mean different things • nuclear force field • distribution of charges • nuclear mass distribution R=roA1/3

  19. Nuclear Force Radii • The radius of the nuclear force field must be less than the distance of closest approach (do) • d = distance from center of nucleus • T’ =  particle’s kinetic energy • T =  particle’s initial kinetic energy • do = distance of closest approach in a head on collision when T’=0 • do~10-20 fm for Cu and 30-60 fm for U http://hyperphysics.phy-astr.gsu.edu/hbase/rutsca.html#c1

  20. Measurement of Nuclear Radii • Any positively charged particle can be used to probe the distance • nuclear (attractive) forces become significant relative to the Coulombic (repulsive force) • Neutrons can be used but require high energy • neutrons are not subject to Coulomb forces • high energy needed for de Broglie wavelengths small compared to nuclear dimensions • at high energies, nuclei become transparent to neutrons • Small cross sections

  21. Electron Scattering • Using moderate energies of electrons, data is compatible with nuclei being spheres of uniformly distributed charges • High energy electrons yield more detailed information about the charge distribution • no longer uniformly charged spheres • Radii distinctly smaller than indicated by methods that determine nuclear force radii • Re (half-density radius)~1.07 fm • de (“skin thickness”)~2.4 fm

  22. Nuclear potentials • Scattering experimental data have has approximate agreement the Square-Well potential • Woods-Saxon equation better fit • Vo=potential at center of nucleus • A=constant~0.5 fm • R=distance from center at which V=0.5Vo (for half-potential radii) • or V=0.9Vo and V=0.1Vo for a drop-off from 90 to 10% of the full potential • ro~1.35 to 1.6 fm for Square-Well • ro~1.25 fm for Woods-Saxon with half-potential radii, • ro~2.2 fm for Woods-Saxon with drop-off from 90 to 10% • Nuclear skin thickness

  23. Nucleus Fraction of nucleons in the “skin” 12C 0.90 24Mg 0.79 56Fe 0.65 107Ag 0.55 139Ba 0.51 208Pb 0.46 238U 0.44 Nuclear Skin

  24. Spin • Nuclei possess angular momentaIh/2 • I is an integral or half-integral number known as nuclear spin • For electrons, generally distinguish between electron spin and orbital angular momentum • Protons and neutrons have I=1/2 • Nucleons in nucleus contribute orbital angular momentum (integral multiple of h/2 ) and their intrinsic spins (1/2) • Protons and neutrons can fill shell (shell model) • Shells have orbital angular momentum like electron orbitals (s,p,d,f,g,h,i,….) • spin of even-A nucleus is zero or integral • spin of odd-A nucleus is half-integral • All nuclei of even A and even Z have I=0 in ground state

  25. Magnetic Moments • Nuclei with nonzero angular momenta have magnetic moments • From spin of protons and neutrons • Bme/Mp is unit of nuclear magnetic moments • nuclear magneton • Measured magnetic moments tend to differ from calculated values • Proton and neutron not simple structures

  26. Methods of measurements • Hyperfine structure in atomic spectra • Atomic Beam method • Element beam split into 2I+1 components in magnetic field • Resonance techniques • 2I+1 different orientations • Quadrupole Moments: q=(2/5)Z(a2-c2), R2 = (1/2)(a2 + c2)= (roA1/3)2 • Data in barns, can solve for a and c • Only nuclei with I1/2 have quadrupole moments • Non-spherical nuclei • Interactions of nuclear quadrupole moments with the electric fields produced by electrons in atoms and molecules give rise to abnormal hyperfine splittings in spectra • Methods of measurement: optical spectroscopy, microwave spectroscopy, nuclear resonance absorption, and modified molecular-beam techniques

  27. Parity • System wave function sign change if sign of the space coordinates change • system has odd or even parity • Parity is conserved • even+odd=odd, even+even=even, odd+odd=odd • allowed transitions in atoms occur only between an atomic state of even and one of odd parity • Parity is connected with the angular-momentum quantum number l • states with even l have even parity • states with odd l have odd parity

  28. Topic review • Understand role of nuclear mass in reactions • Use mass defect to determine energetics • Binding energies, mass parabola, models • Determine Q values • How are nuclear shapes described and determined • Potentials • Nucleon distribution • Quantum mechanical terms • Used in description of nucleus

  29. Study Questions • What do binding energetics predict about abundance and energy release? • Determine and compare the alpha decay Q values for 2 even and 2 odd Np isotopes. Compare to a similar set of Pu isotopes. • What are some descriptions of nuclear shape? • Construct a mass parabola for A=117 and A=50 • What is the density of nuclear material? • Describe nuclear spin, parity, and magnetic moment

  30. Pop Quiz • Using the appropriate mass excess data calculate the following Q values for 212Bi. Show the reaction • b-decay • b+decay • EC • Alpha decay • Which decay modes are likely? • Send answers as e-mail or bring to next class meeting • Provide comments in blog when complete

More Related