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Errors in Hypothesis Testing. 2 TYPES OF ERRORS. TRUE CASE H A is true H A is false WE Accept H A SAY Do not Accept H A. TYPE I ERROR. CORRECT. PROB = α. TYPE II ERROR. CORRECT. PROB = β. α is set by the decision maker. β varies and depends on:
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Errors in Hypothesis Testing
2 TYPES OF ERRORS TRUE CASE HAis true HAis false WE Accept HA SAY Do not Accept HA TYPE I ERROR CORRECT PROB = α TYPE II ERROR CORRECT PROB = β α is set by the decision maker β varies and depends on: (1) α; (2) n; (3) the true value of
Relationship Between and • is the Probability of making a Type II error • i.e. the probability of not concluding HA is true when it is • depends on the true value of • The closer the true value of is to its hypothesized value, the more likely we are of not concluding that HA is true -- i.e. is large (closer to 1) • is calculated BEFOREa sample is taken • We do not use the results of a sample to calculate
The Hypothesis Test CALCULATING • Example: If we take a sample of n = 49, with = 4.2, “What is the probability we will get a sample from which we would not conclude > 25 when really = 25.5?” (Use = .05) REWRITE REJECTION REGION IN TERMS OF
That’s a TYPE II ERROR!! P(Making this error) = CALCULATING (cont’d) • So when = 25.5, • If we get an > 25.987, we will correctly conclude that > 25 • If we get an < 25.987 we will not conclude that > 25 even though really = 25.5
β CALCULATING (cont’d) • So what is P(not getting an > 25.987 when really = 25.5? That is P(getting an < 25.987)? Calculate z = (25.987 - 25.5)/(4.2/ ) .81 • is the area to theleftof .81 for a “>” test • P(Z < .81) = .7910
DO NOT ACCEPT HA WRONG Prob = =.7910 ACCEPT HA RIGHT! “>” TestDetermining When = 25.5 .7910 25.5 25.987 0 .81 Z
β What is When = 27? • So what is P(not getting an > 25.987 when really = 27? That is P(getting an < 25.987)? Calculate z = (25.987 - 27)/(4.2/ ) -1.69 • is the area to theleftof -1.69 for a “>” test • P(Z < -1.69) = .0455 This shows that the further the true value of is from the hypothesized value of , the smallerthe value of β; that is we are less likely to NOT conclude that HA is true (and it is!)
DO NOT ACCEPT HA WRONG Prob = =.0455 ACCEPT HA RIGHT! “>” TestDetermining When = 27 .0455 25.987 27 -1.69 0 Z
The Hypothesis Test for “<” Tests • For n = 49, = 4.2, “What is the probability of not concluding that < 27, when really is 25.5? (With = .05) • This time is the area to the right of
β What is When = 25.5? • So what is P(not getting an < 26.013 when really = 25.5? That is P(getting an > 26.013)? Calculate z = (26.013 – 25.5)/(4.2/ ) .86 • is the area to therightof .86 for a “<” test • P(Z > .86) = 1 - .8051 = .1949
DO NOT ACCEPT HA WRONG Prob = =.1949 ACCEPT HA RIGHT! .1949 “<” TESTDetermining When = 25.5 .8051 25.5 26.013 0 .86 Z
The Hypothesis Test for “” Tests • For n = 49, = 4.2, “What is the probability of not concluding that 26, when really is 25.5? (With = .05) • This time is the area in the middle between the two critical values of
β What is When = 25.5? • So what is P(not getting an < 24.824 or > 27.176 when really = 25.5? That is P(24.824 < < 27.176)? Calculate z’s = (24.824 – 25.5)/(4.2/ ) -1.13 and = (27.176 – 25.5)/(4.2/ ) 2.79 • is the areain between -1.13 and 2.79 for a “” test • P(Z < 2.79) = .9974 • P(Z < -1.13) = .1292 P(-1.13 < Z < 2.79 = .9974 - .1292 = .8682
DO NOT ACCEPT HA WRONG Prob = =.9974 – .1292 =.8682 ACCEPT HA RIGHT! .8682 .9974 .1292 “” TESTDetermining When = 25.5 24.824 25.5 27.176 -1.13 0 2.79 Z
The Power of a Test = 1 - • is the Probability of making a Type II error • i.e. the probability of not concluding HA is true when it is • depends on the true value of and sample size, n • The Power of the test for a particular value of is defined to be the probability of concluding HA is true when it is -- i.e. 1 -
Power Curve Characteristics • The power increases with: • Sample Size, n • The distance the true value of μ is from the hypothesized value of μ
n = 49 n = 25 α = .05 Power Curves For HA: μ 26With n = 25 and n = 49
Calculating Using Excel“> Tests” Suppose H0 is = 25; = 4.2, n = 49, = .05 “>” TESTS: HA: > 25 and we want when the true value of = 25.5 1) Calculate the criticalx-bar value = 25 + NORMSINV(.95)*(4.2/SQRT(49)) 2) Calculate z =(criticalx-bar -25.5)/ (4.2/SQRT(49)) 3) Calculate the the probability of getting a z- value < than this critical z value: -- this is =NORMSDIST(z)
Calculating Using Excel“< Tests” Suppose H0 is = 27; = 4.2, n = 49, = .05 “< TESTS”: HA: < 27 and we want when the true value of = 25.5 1) Calculate the critical x-bar value = 27 - NORMSINV(.95)*(4.2/SQRT(49)) 2) Calculate z =(criticalx-bar -25.5)/ (4.2/SQRT(49)) 3) Calculate the the probability of getting a z- value > than the critical value: -- this is =1-NORMSDIST(z)
Calculating Using Excel“ Tests” Suppose H0 is = 26; = 4.2, n = 49, = .05 TESTS: HA: 26 and we want when the true value of = 25.5 1) Calculate the critical upperx-barU value and the lower criticalx-barL value = 26 - NORMSINV(.975)*(4.2/SQRT(49)) (x-barL) = 26 + NORMSINV(.975)*(4.2/SQRT(49)) (x-barU) 2) Calculate zU=(x-barU-25.5)/ (4.2/SQRT(49)) and zL=(x-barL-25.5)/ (4.2/SQRT(49)) 3) Calculate the the probability of getting an z- value in between zL and zU - this is =NORMSDIST(zU) - NORMSDIST(zL)
=B3+NORMSINV(1-B2)*(B5/SQRT(B6)) =(B8-B7)/(B5/SQRT(B6)) =NORMSDIST(B9) =1-B10 β for “>” Tests
=B3-NORMSINV(1-B2)*(B5/SQRT(B6)) =(B8-B7)/(B5/SQRT(B6)) =1-NORMSDIST(B9) =1-B10 β for “<” Tests
=B3-NORMSINV(1-B2/2)*(B5/SQRT(B6)) =B3+NORMSINV(1-B2/2)*(B5/SQRT(B6)) =(B8-B7)/(B5/SQRT(B6)) =(B9-B7)/(B5/SQRT(B6)) =NORMSDIST(B11)-NORMSDIST(B10) =1-B12 β for “” Tests
REVIEW • Type I and Type II Errors • = Prob (Type I error) • = Prob (Type II error) -- depends on , n and α • How to calculate for: • “>” Tests • “<” Tests • “” Tests • Power of a Test at = 1- • How to calculate using EXCEL