270 likes | 497 Views
Komponenten. SiO 2 - Al 2 O 3 - H 2 O. Phasen. Kyanite Ky Al 2 SiO 5 Sillimanite Si Al 2 SiO 5 Andalusite And Al 2 SiO 5 -Quartz aQz SiO 2 -Quartz bQz SiO 2 Kaolinite Kln AL 2 Si 2 O 5 (OH) 4 Pyrophyllite Prl AL 2 Si 4 O 10 (OH) 2 Water W H 2 O.
E N D
Komponenten SiO2 - Al2O3 - H2O Phasen Kyanite Ky Al2SiO5 Sillimanite Si Al2SiO5 Andalusite And Al2SiO5 -QuartzaQz SiO2 -QuartzbQz SiO2 Kaolinite Kln AL2Si2O5(OH)4 Pyrophyllite Prl AL2Si4O10(OH)2 Water W H2O Nur stabile Reaktionen
Komponenten SiO2 - Al2O3 - H2O Phasen Kyanite Ky Al2SiO5 Sillimanite Si Al2SiO5 Andalusite And Al2SiO5 -QuartzaQz SiO2 -QuartzbQz SiO2 Nur stabile Reaktionen
Komponenten SiO2 - Al2O3 - H2O Phasen Kyanite Ky Al2SiO5 Sillimanite Si Al2SiO5 Andalusite And Al2SiO5 -QuartzaQz SiO2 -QuartzbQz SiO2 alle Reaktionen
Komponenten SiO2 - Al2O3 - H2O Phasen Kyanite Ky Al2SiO5 Sillimanite Si Al2SiO5 Andalusite And Al2SiO5 -QuartzaQz SiO2 -QuartzbQz SiO2 alle Reaktionen
Al2SiO5 Al2SiO5
T ? T ?
Gesucht: für 4000 Bar und 10000 Bar: ∆aG(Sillimanit) = ∆aG(Kyanit) ∆aG(Sillimanit) - ∆aG(Kyanit) = 0 T ? T ?
Sillimanit - Kyanite Sillimanit Kyanite V0 [J/Bar] 4.9900 4.4090 0.581
Sillimanit - Kyanite Sillimanit Kyanite V0 [J/Bar] 4.9900 4.4090 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J
Sillimanit - Kyanite Sillimanit Kyanite V0 [J/Bar] 4.9900 4.4090 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J Sillimanit - Kyanite ∆fG [J/mol] Sillimanit Kyanite 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641
Sillimanit - Kyanite Sillimanit Kyanite V0 [J/Bar] 4.9900 4.4090 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J Sillimanit - Kyanite ∆fG [J/mol] + 2324 + 5810 Sillimanit Kyanite 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641
Sillimanit - Kyanite Sillimanit Kyanite V0 [J/Bar] 4.9900 4.4090 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J Sillimanit - Kyanite ∆fG [J/mol] + 2324 + 5810 Sillimanit Kyanite 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641 892 -244 135 -831
Sillimanit - Kyanite Sillimanit Kyanite V0 [J/Bar] 4.9900 4.4090 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J Sillimanit - Kyanite ∆fG [J/mol] + 2324 + 5810 Sillimanit Kyanite 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641 892 -244 135 -831 678.5 K 1014.0 K
892 -244
P = 4000 Bar f1 = a·x1 + b f2 = a·x2 + b ∆rG(Sil-Ky) 892 700 K -244 600
P = 4000 Bar f1 = a·x1 + b f2 = a·x2 + b ∆rG(Sil-Ky) 892 700 K -244 600 Nullpunkt (∆rG = 0) :
P = 4000 Bar f1 = a·x1 + b a = (∂∆rG/∂T)P = -∆rS ∆rG(Sil-Ky) ∆rS = 11.69 J/K·mol 892 700 K -244 600
P = 4000 Bar f1 = a·x1 + b a = (∂∆rG/∂T)P = -∆rS ∆rG(Sil-Ky) ∆rS = 11.69 J/K·mol 892 700 K -244 600
P = 10000 Bar f1 = a·x1 + b f2 = a·x2 + b ∆rG(Sil-Ky) 135 1100 K 1000 -831 Nullpunkt (∆rG = 0) :
1014.0 K 678.5 K
1014.0 K 678.5 K
Kyanit Sillimanit 1014.0 K 678.5 K