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TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz.

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  1. TUTORIAL INSTRUCTIONS: Carefully go through the tutorial, step by step. You may return to any section, as necessary. Once you are satisfied that you understand the concepts and procedures, click CLOSE to get out of the tutorial mode. You will then be taken to the post-quiz. CLICK TO CONTINUE

  2. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY The element sulfur,S(s), contains 6.022 x 1023S atoms/mole. The compound bromine, Br2(l), contains 6.022 x 1023Br2 molecules/mole. The compound carbon dioxide, CO2(g), contains 6.022 x 1023 CO2 molecules/mole . CLICK TO CONTINUE

  3. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY S(s) = 32.066 g/mol Br2(l) = 159.808 g/mol CO2(g) = 44.010 g/mol CLICK TO CONTINUE

  4. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY At room temperature and pressure: S(s)  16 cm3/mol Br2(l)  51 cm3/mol CO2(g)  2 x 104 cm3/mol CLICK TO CONTINUE

  5. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY sulfur atoms, S atomic weight = 32.066  32.066 g S/mol S bromine molecules, Br2 atomic weight = 79.904  molecular weight 159.808  159.808 g Br2/mol Br2 carbon dioxide molecules, CO2 atomic weights carbon 12.011, oxygen 15.9994 molecular weight 44.010  44.010 g CO2/mol CO2 CLICK TO CONTINUE

  6. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY • Convert 30 g carbon to moles. C: atomic weight 12.011 12.011 g C/mol C CLICK TO CONTINUE

  7. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 30 g C to mol.) mass (g) carbon  moles carbon CLICK TO CONTINUE

  8. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 30 g C to mol.) 1 12.011 mole C g C _________ x 30 g C 30 mole C 12.011 = 2.5 mol C CLICK TO CONTINUE

  9. 2. Convert 3.5 liters of ammonia at S.T.P. to moles.

  10. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH3 at S.T.P. to mol.) 22.414 L/mole NH3(g) (at S.T.P.) volume (L) ammonia  moles ammonia CLICK TO CONTINUE

  11. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (Convert 3.5 L NH3 at S.T.P. to mol.) mol NH3 L NH3 1 22.414 ___________ 3.5 L NH3 x 3.5 mol NH3 22.414 = 0.16 mol NH3 CLICK TO CONTINUE

  12. 3. How many moles of glucose are in 10 mL of a 0.5 molar aqueous solution? M (molar) = mol solute/L solution 0.5 M glucose = 0.5 mol glucose/1 L soln

  13. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) volume (mL) solution  volume (L) solution  moles solvent CLICK TO CONTINUE

  14. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 1 1000 or 10 mL solutionx 1 L 103 mL L mL ______ 10 mL solution x or 10 mL solutionx 10-3 L 1 mL CLICK TO CONTINUE

  15. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) x mol glucose L solution 0.5 1 10 mL solutionx 1 L 1000 mL or 10 mL solutionx 1 L 103 mL or 10 mL solutionx 10-3 L 1 mL x mol glucose L solution 0.5 1 x mol glucose L solution 0.5 1 CLICK TO CONTINUE

  16. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 10 mL solutionx 1 L x 0.5 mol glucose 1000 mL 1 L solution or 10 mL solutionx 1 L x 0.5 mol glucose 103 mL 1 L solution or 10 mL solutionx 10-3L x 0.5 mol glucose 1 mL 1 L solution CLICK TO CONTINUE

  17. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# mol glucose in 10 mL 0.5 M soln?) 10 x 0.5 mol glucose 1000 or 10 x 0.5 mol glucose 103 or 10 x 10-3 x 0.5 mol glucose = 0.005 or 5 x 10-3 mol glucose CLICK TO CONTINUE

  18. 4. How many atoms are present in 4.0 moles of phosphine, PH3?

  19. (# atoms in 4.0 mol PH3?) 4.0 atoms/molecule PH3 moles phosphine  molecules phosphine  atoms CLICK TO CONTINUE

  20. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# atoms in 4.0 mol PH3?) 6.02 x 1023 1 molecules PH3 mol PH3 4.0 mol PH3 x _____________________ x atoms molecule PH3 4 1 CLICK TO CONTINUE

  21. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# atoms in 4.0 mol PH3?) ___________________ 4.0 mol PH3x 6.02 x 1023molecules PH3 1 mol PH3 x 4 atoms 1 molecules PH3 4.0 x 6.02 x 1023 x 4 atoms = 9.6 x 1024 atoms CLICK TO CONTINUE

  22. 5. How many electrons are lost by ionization of 0.65 moles of calcium?

  23. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?) CaCa2+ + 2e moles calcium  atoms calcium  electrons CLICK TO CONTINUE

  24. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?) 6.02 x 1023 1 atoms Ca mol Ca __________________ 0.65 mol Ca x x electrons atom Ca 2 1 CLICK TO CONTINUE

  25. LISTEN THOUGHTFULLY GO AT YOUR OWN PACE MAKE NOTES AS NECESSARY (# electrons lost by 0.65 mol Ca?) 0.65 mol Ca x 6.02 x 1023 atoms Ca 1 mol Ca x 2 electrons 1 atom Ca 0.65 x 6.02 x 1023 x 2 electrons = 7.8 x 1023 electrons CLICK TO CONTINUE END OF TUTORIAL

  26. RETURN TO TUTORIAL OR GO TO POST-QUIZ

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