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Limiting Reactant

Limiting Reactant. Which will run out first?. Each reactant’s amount will be provided, either in moles or mass Two methods can be used Trial Method Advancement Method. Trial Method.

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Limiting Reactant

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  1. Limiting Reactant

  2. Which will run out first? • Each reactant’s amount will be provided, either in moles or mass • Two methods can be used • Trial Method • Advancement Method

  3. Trial Method • Use mass-mass stoichiometry calculation to determine how much Reactant B will be required to completely consume Reactant A. • Sample Problem: 15.0g of N2 reacts with 15.0g of H2 to make ammonia according to the equation N2 + 3H2 → 2NH3 • How much ammonia can be made?

  4. Solution to Ex. 1 • Trial method calculation • Advancement Method • Moles of each reactant (n)/coefficient then compare results • N2: 15.0g/28.02g/mol/1mol = 0.535 • H2: 15.0g/2.016g/mol/3mol = 2.48 • Lowest value is ALWAYS LR

  5. And the point is… • Since it runs out first, the limiting reactant must be determined in order to determine the maximum theoretical yield for this reaction. • How much ammonia (NH3) can be made from these amounts of reactants? • Trial method calculation

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