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8.2A Factoring using Distributive Property

8.2A Factoring using Distributive Property. Objective The student will be able to: Factor using the greatest common factor (GCF). Review: What is the GCF of 25a 2 and 15a?. 5a Let’s go one step further… Ex 1) FACTOR out the GCF: 25a 2 + 15a. Find the GCF and divide each term

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8.2A Factoring using Distributive Property

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  1. 8.2A Factoring using Distributive Property ObjectiveThe student will be able to: Factor using the greatest common factor (GCF).

  2. Review: What is the GCF of 25a2 and 15a? 5a Let’s go one step further… Ex 1) FACTOR out the GCF: 25a2 + 15a. Find the GCF and divide each term 25a2 + 15a = 5a( ___ + ___ ) Check your answer by distributing. 5a 3

  3. Find the GCF 6x2 Divide each term by the GCF 18x2 – 12x3 = 6x2( ___ – ___ ) Check your answer by distributing. Ex 2) Factor 18x2 – 12x3. 3 2x

  4. Ex 3) Factor 28a2b + 56abc2. GCF = 28ab Divide each term by the GCF 28a2b + 56abc2 = 28ab ( ___ + ___ ) Check your answer by distributing. 28ab(a + 2c2) a 2c2

  5. Ex 4) Factor 20x2 – 24xy • x(20 – 24y) • 2x(10x – 12y) • 4(5x2 – 6xy) • 4x(5x – 6y)

  6. Ex 5) Factor 28a2 + 21b – 35b2c2 GCF = 7 Divide each term by the GCF 28a2 + 21b – 35b2c2 = 7 ( ___ + ___ – ____ ) Check your answer by distributing. 7(4a2 + 3b – 5b2c2) 4a2 3b 5b2c2

  7. Ex 6) Factor 16xy2 – 24y2z + 40y2 • 2y2(8x – 12z + 20) • 4y2(4x – 6z + 10) • 8y2(2x – 3z + 5) • 8xy2z(2 – 3 + 5)

  8. 8.2A HW pg. 479 #1 – 4 all,15 – 20 all64, 68, 84 (13 problems)

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