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2.1 a and b. Finding the vertex and y-intercept from standard form Graphing in standard form. These properties can be generalized to help you graph quadratic functions. Helpful Hint. When a is positive, the parabola is happy (U). When the a negative, the parabola is sad ( ). U.
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2.1 a and b Finding the vertex and y-intercept from standard form Graphing in standard form
These properties can be generalized to help you graph quadratic functions.
Helpful Hint When a is positive, the parabola is happy (U). When the a negative, the parabola is sad ( ). U The Axis of Symmetry is the same as the x-coordinate of the vertex.
The axis of symmetry is given by . Example 2A: Graphing Quadratic Functions in Standard Form Consider the function f(x) = 2x2 – 4x + 5. a. Determine whether the graph opens upward or downward. Because a is positive, the parabola opens upward. b. Find the axis of symmetry. Substitute –4 for b and 2 for a. The axis of symmetry is the line x = 1.
Example 2A: Graphing Quadratic Functions in Standard Form Consider the function f(x) = 2x2 – 4x + 5. c. Find the vertex. The vertex lies on the axis of symmetry, so the x-coordinate is 1. The y-coordinate is the value of the function at this x-value, or f(1). f(1) = 2(1)2 – 4(1) + 5 = 3 The vertex is (1, 3). d. Find the y-intercept. Because c = 5, the intercept is 5.
Example 2A: Graphing Quadratic Functions in Standard Form Consider the function f(x) = 2x2 – 4x + 5. e. Graph the function. Graph by making a table of values with the x-coordinate of the vertex in the center.
The axis of symmetry is given by . Example 2B: Graphing Quadratic Functions in Standard Form Consider the function f(x) = –x2 – 2x + 3. a. Determine whether the graph opens upward or downward. Because a is negative, the parabola opens downward. b. Find the axis of symmetry. Substitute –2 for b and –1 for a. The axis of symmetry is the line x = –1.
Example 2B: Graphing Quadratic Functions in Standard Form Consider the function f(x) = –x2 – 2x + 3. c. Find the vertex. The vertex lies on the axis of symmetry, so the x-coordinate is –1. The y-coordinate is the value of the function at this x-value, or f(–1). f(–1) = –(–1)2 – 2(–1) + 3 = 4 The vertex is (–1, 4). d. Find the y-intercept. Because c = 3, the y-intercept is 3.
Example 2B: Graphing Quadratic Functions in Standard Form Consider the function f(x) = –x2 – 2x + 3. e. Graph the function. Graph by making a table of values with the x-coordinate of the vertex in the center.
b. The axis of symmetry is given by . Check It Out! Example 2a For the function, (a) determine whether the graph opens upward or downward, (b) find the axis of symmetry, (c) find the vertex, (d) find the y-intercept, and (e) graph the function. f(x)= –2x2 – 4x a. Because a is negative, the parabola opens downward. Substitute –4 for b and –2 for a. The axis of symmetry is the line x = –1.
Check It Out! Example 2a f(x)= –2x2 – 4x c. The vertex lies on the axis of symmetry, so the x-coordinate is –1. The y-coordinate is the value of the function at this x-value, or f(–1). f(–1) = –2(–1)2 – 4(–1) = 2 The vertex is (–1, 2). d. Because c is 0, the y-intercept is 0.
Check It Out! Example 2a f(x)= –2x2 – 4x e. Graph the function. Graph by making a table of values with the x-coordinate of the vertex in the center.
b. The axis of symmetry is given by . The axis of symmetry is the line . Check It Out! Example 2b For the function, (a) determine whether the graph opens upward or downward, (b) find the axis of symmetry, (c) find the vertex, (d) find the y-intercept, and (e) graph the function. g(x)= x2 + 3x – 1. a. Because a is positive, the parabola opens upward. Substitute 3 for b and 1 for a.
c. The vertex lies on the axis of symmetry, so the x-coordinate is . The y-coordinate is the value of the function at this x-value, or f(). f( ) = ( )2 + 3( ) – 1 = The vertex is ( , ). Check It Out! Example 2b g(x)= x2 + 3x – 1 d. Because c = –1, the intercept is –1.
Check It Out! Example2 g(x)= x2 + 3x – 1 e. Graph the function. Graph by making a table of values with the x-coordinate of the vertex in the center.
Lesson Quiz: Part I Consider the function f(x)= 2x2 + 6x – 7. 1. Determine whether the graph opens upward or downward. 2. Find the axis of symmetry. 3. Find the vertex. 4. Identify the maximum or minimum value of the function. 5. Find the y-intercept. upward x = –1.5 (–1.5, –11.5) min.: –11.5 –7
Lesson Quiz: Part II Consider the function f(x)= 2x2 + 6x – 7. 6. Graph the function. By making a table