1 / 4

S e c t i o n 9 . 4

S e c t i o n 9 . 4. Solving Polynomial Equations in Factored Form. Algebra I Notes Section 9.4: Solving Polynomial Equations in Factored Form In this lesson we will learn how to solve quadratic and other polynomial equations in factored form.

fairly
Download Presentation

S e c t i o n 9 . 4

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Section9.4 Solving Polynomial Equations in Factored Form

  2. Algebra I Notes Section 9.4: Solving Polynomial Equations in Factored Form In this lesson we will learn how to solve quadratic and other polynomial equations in factored form. A polynomial is in ________________ if it is written as the product of two or more linear factors. When solving equations in factored form we must use the _____________________ to find the solutions. Zero Product Property If ab = 0, then a = 0 or b = 0 or both a & b = 0 Examples: Solve the polynomial equations using the zero product property. 1) (x – 4)(x + 1) = 0 2) factored form zero product property A binomial so nice, write it twice x – 4 = 0 x + 1 = 0 x + 8 = 0 x + 8 = 0 x = 4 x = -1 x = -8 (Dbl. Root)

  3. 3) (3x – 2)(4x + 3)(x + 4) = 0 • Sometimes to solve a polynomial equation using the zero-product property, you may need to factor out the ________________________________ of the polynomial’s terms. This is a monomial with an integer coefficient that divides evenly into each term • or a common variable in every term. • Example: Factor out the greatest common monomial factor. • 4) 8x + 12y 5) 14y2 – 21y 3x – 2 = 0 4x + 3 = 0 x + 4 = 0 3x = 2 4x = -3 x = -4 x = 2/3 x = -3/4 greatest common monomial factor 4(2x + 3y) 7y(2y – 3)

  4. Examples: Solve the following equations using GCF. • 6 ) 3x2+ 18x = 0 7) 4x2 = 14x 3x(x + 6) = 0 4x2 – 14x = 0 2x(2x – 7) = 0 3x = 0 x + 6 = 0 2x = 0 2x – 7 = 0 x = 0 x = -6 x = 0 2x = 7 x = 7/2

More Related