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Learn to graphically represent and solve linear, combined, and absolute value inequalities using set and interval notation. Understand interval notation, set notation, and solving combined and absolute value inequalities. Practice interpreting and graphing solutions.
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A.8 Interval Notation; Solving Inequalities Students will be able to (swbat): 1. Represent Solutions to Inequalities Graphically, and by Using Set & Interval Notation. 2. Solve Linear, Combined, and Absolute Value Inequalities.
Inequalities – Interval Notation If the variable is on the left, the arrow points the same direction as the inequality. [( smallest, largest )] Parentheses: endpoint is not included <, > Bracket: endpoint is included ≤, ≥ Infinity: always uses a parenthesis x < 2 ( –∞, 2) x ≥ 2 [2, ∞) 4 < x < 9 3-part inequality (4, 9)
Inequalities – Set Notation {variable | condition } pipe { x|x 5} The set of all xsuch thatx is greater than or equal to 5. x < 2 x < 2 { x | } ( –∞, 2) x ≥ 2 [2, ∞) { x | x ≥ 2} 4 < x < 9 (4, 9) { x | 4 < x < 9}
Inequalities Interval Notation: (-7,3] Set Notation: {x }| Graph, then write in interval and set notation. 1 < a < 6
Solving Inequalities If we multiply (or divide) by a negative, reverse the direction of the inequality!!!!!
Solving Inequalities Solve then graph the solution and write it in interval notation and set notation. ] Interval Notation: (– ∞, –3 ] Set Notation: { k | k ≤ –3 }
Solving Combined Inequalities Solve the inequality 4 ≤ 2x + 2 ≤ 10, graph your solution, and write your solution in both interval and set notation.
Inequalities Involving Absolute Value │x│< a is equivalent to -a < x < a (-a,a) │x│≤ a is equivalent to -a ≤ x ≤ a [-a,a] │x│> a is equivalent to x< -a or x>a (-∞,-a)U(a,∞) │x│≥ a is equivalent to x≤ -a or x≥a (-∞,-a]U[a,∞)
Solving an Absolute Value Inequality Solve │2u + 5 │≤ 7, graph the solution set, and write the solution in both set and interval notation.
Methacton Merchandise The Methacton Merchandise salesperson is paid a commission of $10 plus 50% of the selling price in excess of the cost to make the merchandise (owner’s cost). The owner of Methacton Merchandise claims that her products sell for at least owner’s cost plus $10 and at most owner’s cost plus $60. For each sale made, over what range can the salesperson expect the commission to vary?
Methacton Merchandise 10 + .5(10) = $15.00 10 + .5(60) = $40.00 15.00 ≤ x ≤ 40.00