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MA242.003

MA242.003. Day 67 April 22, 2013 Section 13.7: Stokes’s Theorem Section 13.4: Green’s Theorem. Remark about Final Exam:. 1. Use your 4 tests (and their study guides) to prepare for the final exam. Remark about Final Exam:.

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MA242.003

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  1. MA242.003 Day 67 April 22, 2013 Section 13.7: Stokes’s Theorem Section 13.4: Green’s Theorem

  2. Remark about Final Exam: 1. Use your 4 tests (and their study guides) to prepare for the final exam.

  3. Remark about Final Exam: 1. Use your 4 tests (and their study guides) to prepare for the final exam. All problems on the final (except the LAST TWO) will be of the same TYPE as the problems on the 4 tests

  4. Remark about Final Exam: 1. Use your 4 tests (and their study guides) to prepare for the final exam. All problems on the final (except the LAST TWO) will be of the same TYPE as the problems on the 4 tests For example, you should expect a double integral problem on the final exam because double integrals were covered on the 3rd test.

  5. Remark about Final Exam: 1. Use your 4 tests (and their study guides) to prepare for the final exam. All problems on the final (except the LAST TWO) will be of the same TYPE as the problems on the 4 tests For example, you should expect a double integral problem on the final exam because double integrals were covered on the 3rd test. 3. There will be one problem each covering Stokes’ theorem (13.7) and the Divergence Theorem (13.8)

  6. In sections 13.7 and 13.8 we will study two famous integral theorems of vector calculus.

  7. In sections 13.7 and 13.8 we will study two famous integral theorems of vector calculus. The theorems may be thought of as the 2 and 3 dimensional versions of the following integral formulas

  8. The theorems may be thought of as the 2 and 3 dimensional versions of the following integral formulas Fundamental Theorem of Calculus

  9. The theorems may be thought of as the 2 and 3 dimensional versions of the following integral formulas Fundamental Theorem of Calculus Fundamental Theorem for Line Integrals

  10. We will first discuss Green’s theorem before considering Stokes’ Theorem, since Green’s theorem is needed in the proof of Stokes’ Theorem.

  11. 13.4: Green’s Theorem Let C be a positively oriented, piecewise-smooth simple closed curved in the plane,

  12. 13.4: Green’s Theorem Let C be a positively oriented, piecewise-smooth simple closed curved in the plane, positively oriented means counter clockwise

  13. 13.4: Green’s Theorem Let C be a positively oriented, piecewise-smooth simple closed curved in the plane, piecewise-smooth means composed of a finite number of smooth sub-curves

  14. 13.4: Green’s Theorem Let C be a positively oriented, piecewise-smooth simple closed curved in the plane, simple closed means starts and ends at the same point, with no other self-intersections

  15. 13.4: Green’s Theorem Let C be a positively oriented, piecewise-smooth, simple closed curved in the plane, and let D be the region bounded by C. If P and Q have continuous partial derivatives on an open region containing D, then

  16. 13.4: Green’s Theorem Let C be a positively oriented, piecewise-smooth, simple closed curved in the plane, and let D be the region bounded by C. If P and Q have continuous partial derivativeson an open region containing D, then

  17. Proof : First a definition and a lemma we will need in the proof.

  18. Proof : First a definition and a lemma we will need in the proof.

  19. Proof : First a definition and a lemma we will need in the proof. Lemma:

  20. Proof of Green’s Theorem for a special type of region: Notice first that since P(x,y) and Q(x,y) are independent of each other, to prove Green’s theorem

  21. Proof of Green’s Theorem for a special type of region: Notice first that since P(x,y) and Q(x,y) are independent of each other, to prove Green’s theorem It is sufficient to prove the following two formulas separately:

  22. Proof of Green’s Theorem for a special type of region: Notice first that since P(x,y) and Q(x,y) are independent of each other, to prove Green’s theorem It is sufficient to prove the following two formulas separately: I’m going to prove the second formula

  23. Proof of Green’s Theorem for a special type of region:

  24. Proof of Green’s Theorem for a special type of region:

  25. Let’s first work on the left-hand-side of the formula using

  26. Now we must work on the right-hand-side of the formula

  27. Now we must work on the right-hand-side of the formula

  28. Now we must work on the right-hand-side of the formula

  29. Now we must work on the right-hand-side of the formula

  30. Now we must work on the right-hand-side of the formula

  31. Now we must work on the right-hand-side of the formula

  32. Now we must work on the right-hand-side of the formula Left-hand-side:

  33. Now we must work on the right-hand-side of the formula *** Left-hand-side: Right-hand-side: Hence we have proved formula ***

  34. The proof of the other formula

  35. The proof of the other formula Is essentially the same as the above and we leave this part as an exercise.

  36. 13.7: Stokes’ Theorem Notice that the integrand in the double integral in Green’s Theorem

  37. 13.7: Stokes’ Theorem Notice that the integrand in the double integral in Green’s Theorem Is the z-component of the curl of F = <P,Q,R>

  38. 13.7: Stokes’ Theorem Notice that the integrand in the double integral in Green’s Theorem Is the z-component of the curl of F = <P,Q,R> Stokes’ theorem is the 3 dimensional version of Greens’ theorem.

  39. First we need the following definition:

  40. First we need the following definition:

  41. First we need the following definition:

  42. First we need the following definition: We will have more to say about this after stating Stokes’ theorem.

  43. See your textbook for the proof of this theorem for special types of surfaces.

  44. This means that in order to determine “positive orientation” for a surface and its boundary curve, we may “deform the surface” WITHOUT tearing it to make the decision easier..

  45. This means that in order to determine “positive orientation” for a surface and its boundary curve, we may “deform the surface” WITHOUT tearing it to make the decision easier.. Example:

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