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Chapter 11: Stoichiometry

CHEMISTRY Matter and Change. Chapter 11: Stoichiometry. Table Of Contents. CHAPTER 11. Section 11.1 Defining Stoichiometry Section 11.2 Stoichiometric Calculations Section 11.3 Limiting Reactants Section 11.4 Percent Yield. Click a hyperlink to view the corresponding slides. Exit.

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Chapter 11: Stoichiometry

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  1. CHEMISTRY Matter and Change Chapter 11: Stoichiometry

  2. Table Of Contents CHAPTER11 Section 11.1 Defining Stoichiometry Section 11.2 Stoichiometric Calculations Section 11.3 Limiting Reactants Section 11.4 Percent Yield Click a hyperlink to view the corresponding slides. Exit

  3. Defining Stoichiometry SECTION11.1 Describethe types of relationships indicated by a balanced chemical equation. reactant:the starting substance in a chemical reaction Statethe mole ratios from a balanced chemical equation. stoichiometry mole ratio The amount of each reactant present at the start of a chemical reaction determines how much product can form.

  4. Defining Stoichiometry SECTION11.1 Particle and Mole Relationships Chemical reactions stop when one of the reactants is used up. Stoichiometryis the study of quantitative relationships between the amounts of reactants used and amounts of products formed by a chemical reaction.

  5. Defining Stoichiometry SECTION11.1 Particle and Mole Relationships (cont.) Stoichiometry is based on the law of conservation of mass. The mass of reactants equals the mass of the products.

  6. Defining Stoichiometry SECTION11.1 Particle and Mole Relationships (cont.)

  7. Defining Stoichiometry SECTION11.1 Particle and Mole Relationships (cont.) A mole ratio is a ratio between the numbers of moles of any two substances in a balanced equation. The number of mole ratios that can be written for any equation is (n)(n – 1) where n is the number of species in the chemical reaction.

  8. Section Check SECTION11.1 Which of the following is a correct mole ratio for the following equation? 2Al(s) + 3Br2(l) → 2AlBr3(s) A.2 mol Al : 3 mol Br B.3 mol Br2 : 2 mol Al C.2 mol AlBr3 : 1 mol Br2 D.2 mol Br : 2 mol Al

  9. Section Check SECTION11.1 How many mole ratios can be written for the following reaction? 4H2(g) + O2(g) → 2H2O(l) A.6 B.4 C.3 D.2

  10. Stoichiometric Calculations SECTION11.2 Listthe sequence of steps used in solving stoichiometric problems. chemical reaction:a process in which the atoms of one or more substances are rearranged to form different substances Solvestoichiometric problems. The solution to every stoichiometric problem requires a balanced chemical equation.

  11. Stoichiometric Calculations SECTION11.2 Using Stoichiometry • All stoichiometric calculations begin with a balanced chemical equation. 4Fe(s) + 3O2(g)  2Fe2O3(s)

  12. Stoichiometric Calculations SECTION11.2 Using Stoichiometry (cont.) Steps to solve mole-to-mole, mole-to-mass, and mass-to-mass stoichiometric problems Write a balanced chemical equation for the reaction. Determine where to start your calculations by noting the unit of the given substance. If mass (in grams) of the given substance is the starting unit, you must convert to moles. If amount (in moles) of the given substance is the starting unit, convert moles of the given substance to moles of the unknown.

  13. Stoichiometric Calculations SECTION11.2 Using Stoichiometry (cont.) 3.The end point of the calculation depends on the desired unit of the unknown substance. If the answer must be in moles, stop you are finished. If the answer must be in grams, convert moles of unknown to grams of unknown using the molar mass as the conversion factor.

  14. Stoichiometric Calculations SECTION11.2 Using Stoichiometry (cont.) • Ex. The carbon dioxide exhaled by astronauts can be removed from a spacecraft by reacting with lithium hydroxide as follows: CO2(g) + LiOH(s)→ Li2CO3(s) An average person exhales about 20 moles of CO2 per day. How many moles of LiOH would be required to maintain 2 astronauts in a spacecraft for three days?

  15. Balance equation: CO2 + 2LiOH → Li2CO3 + H2O Determine moles of given substance: 20moles per person, 2 people = 40moles x 3 days = 120moles of CO2 Convert moles of given substance to moles of unknown: 120 mol CO2 x 2 mol = 240moles of LiOH 1 mol Stoichiometric Calculations SECTION11.2 Using Stoichiometry (cont.)

  16. Section Check SECTION11.2 A chemical reaction equation must be ____ in order to make stoichiometric calculations. A.measured B.controlled C.balanced D.produced

  17. Section Check SECTION11.2 How many moles of CO2 will be produced in the following reaction if the initial amount of reactants was 0.50 moles? 2NaHCO3 → Na2CO + CO2 + H2O A.0.25 B.0.3 C.0.5 D.1.0

  18. Limiting Reactants SECTION11.3 Identifythe limiting reactant in a chemical equation. Identifythe excess reactant, and calculate the amount remaining after the reaction is complete. Calculatethe mass of a product when the amounts of more than one reactant are given. molar mass:the mass in grams of one mole of any pure substance

  19. Limiting Reactants SECTION11.3 limiting reactant excess reactant A chemical reaction stops when one of the reactants is used up.

  20. Limiting Reactants SECTION11.3 Why do reactions stop? Reactions proceed until one of the reactants is used up and one is left in excess. The limiting reactant limits the extent of the reaction and, thereby, determines the amount of product formed. The excess reactantsare all the leftover unused reactants.

  21. Limiting Reactants SECTION11.3 Why do reactions stop? (cont.) Determining the limiting reactant is important because the amount of the product formed depends on this reactant.

  22. Limiting Reactants SECTION11.3 Calculating the Product when a Reactant is Limiting Ex. S8(l) + 4Cl2(g) → 4S2Cl2(l) If 200.0g of sulfur reacts with 100.0g of chlorine, what mass of disulfur dichloride is produced? • Determine moles of reactants

  23. Determine whether the two reactants are in the correct mole ratio, as given in the balanced chemical equation. Only 1.808 mol of chlorine is available for every 1 mol sulfur, instead of the 4mol of chlorine required by the balanced chemical equation, thus chlorine is the limiting reactant. Limiting Reactants SECTION11.3 Calculating the Product when a Reactant is Limiting (cont.)

  24. Calculate the amount of product formed. Limiting Reactants SECTION11.3 Calculating the Product when a Reactant is Limiting (cont.)

  25. Limiting Reactants SECTION11.3 Calculating the Product when a Reactant is Limiting (cont.) • Now that you have determined the limiting reactant and the amount of product formed, what about the excess reactant, sulfur? How much of it reacted? • You need to make a mole-to-mass calculation to determine the mass of sulfur needed to react completely with 1.410 mol of chlorine.

  26. Next, obtain the mass of sulfur needed: Knowing that 200.0g of sulfur is available and only 90.42g is needed, you can calculate the amount of sulfur left unreacted when the reaction ends. Limiting Reactants SECTION11.3 Calculating the Product when a Reactant is Limiting (cont.)

  27. Limiting Reactants SECTION11.3 Calculating the Product when a Reactant is Limiting (cont.) Using an excess reactant can speed up the reaction. Using an excess reactant can drive a reaction to completion.

  28. Section Check SECTION11.3 The mass of the final product in a chemical reaction is based on what? A.the amount of excess reactant B.the amount of limiting reactant C.the presence of a catalyst D.the amount of O2 present

  29. Section Check SECTION11.3 What is the excess reactant in the following reaction if you start with 50.0g of each reactant? P4(s) + 5O2(g) → P4O10(s) A.O2 B.P4 C.Both are equal. D.unable to determine

  30. Percent Yield SECTION11.4 Calculatethe theoretical yield of a chemical reaction from data. process:a series of actions or operations Determinethe percent yield for a chemical reaction. theoretical yield actual yield percent yield Percent yield is a measure of the efficiency of a chemical reaction.

  31. Percent Yield SECTION11.4 How much product? Laboratory reactions do not always produce the calculated amount of products. Reactants stick to containers. Competing reactions form other products.

  32. Percent Yield SECTION11.4 How much product? (cont.) The theoretical yieldis the maximum amount of product that can be produced from a given amount of reactant. The actual yield is the amount of product actually produced when the chemical reaction is carried out in an experiment. The percent yieldof a product is the ratio of the actual yield expressed as a percent.

  33. Percent Yield SECTION11.4 Percent Yield in the Marketplace Percent yield is important in the cost effectiveness of many industrial manufacturing processes.

  34. Section Check SECTION11.4 The amount of product that can be produced from a given amount of reactants based on stoichiometric calculations is: A.actual yield B.percent yield C.theoretical yield D.stoichiometric yield

  35. Section Check SECTION11.4 If the theoretical yield of a chemical reaction that began with 50.0 g of reactant is 25.0 g of product.What is the percent yield if the actual yield is 22.0g of product? A.88% B.44% C.50% D.97%

  36. Stoichiometry CHAPTER11 Resources Chemistry Online Study Guide Chapter Assessment Standardized Test Practice

  37. Defining Stoichiometry SECTION11.1 Study Guide Key Concepts Balanced chemical equations can be interpreted in terms of moles, mass, and representative particles (atoms, molecules, formula units). The law of conservation of mass applies to all chemical reactions. Mole ratios are derived from the coefficients of a balanced chemical equation. Each mole ratio relates the number of moles of one reactant or product to the number of moles of another reactant or product in the chemical reaction.

  38. Stoichiometric Calculations SECTION11.2 Study Guide Key Concepts Chemists use stoichiometric calculations to predict the amounts of reactants used and products formed in specific reactions. The first step in solving stoichiometric problems is writing the balanced chemical equation. Mole ratios derived from the balanced chemical equation are used in stoichiometric calculations. Stoichiometric problems make use of mole ratios to convert between mass and moles.

  39. Limiting Reactants SECTION11.3 Study Guide Key Concepts The limiting reactant is the reactant that is completely consumed during a chemical reaction. Reactants that remain after the reaction stops are called excess reactants. To determine the limiting reactant, the actual mole ratio of the available reactants must be compared with the ratio of the reactants obtained from the coefficients in the balanced chemical equation. Stoichiometric calculations must be based on the limiting reactant.

  40. Percent Yield SECTION11.4 Study Guide Key Concepts The theoretical yield of a chemical reaction is the maximum amount of product that can be produced from a given amount of reactant. Theoretical yield is calculated from the balanced chemical equation. The actual yield is the amount of product produced. Actual yield must be obtained through experimentation. Percent yield is the ratio of actual yield to theoretical yield expressed as a percent. High percent yield is important in reducing the cost of every product produced through chemical processes.

  41. Stoichiometry CHAPTER11 Chapter Assessment What law are all stoichiometric calculations based on? A.law of definite proportions B.law of conservation of mass C.law of conservation of energy D.none of the above

  42. Stoichiometry CHAPTER11 Chapter Assessment The mole ratios can be determined only if what? A.all the reactants are present in equal amounts B.the reactants do not have coefficients C.the products do not have coefficients D.the equation is balanced

  43. Stoichiometry CHAPTER11 Chapter Assessment If the following reaction yields 5 mol NaAu(CN)2, how many moles of Au were present as reactants? (Assume all other reactants are in excess). 4Au(s) + 8NaCN(aq) + O2 + 2H2O(l) → 4NaAu(CN)2(aq) + 4NaOH(aq) A.1 B.4 C.5 D.20

  44. Stoichiometry CHAPTER11 Chapter Assessment In the following reaction, how many moles of NaCN are required to react with 5 mol of Au?4Au(s) + 8NaCN(aq) + O2 + 2H2O(l) → 4NaAu(CN)2(aq) + 4NaOH(aq) A.3 B.5 C.8 D.10

  45. Stoichiometry CHAPTER11 Chapter Assessment In the following reaction, what mass of NaOH is produced if 5.0 moles of NaAu(CN)2 are also produced in the reaction? 4Au(s) + 8NaCN(aq) + O2 + 2H2O(l) → 4NaAu(CN)2(aq) + 4NaOH(aq) A.20 g B.50 g C.200 g D.400 g

  46. Stoichiometry CHAPTER11 Standardized Test Practice The SI base unit of amount is ____. A.the gram B.the kilogram C.the mole D.Avogadro’s number

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