1 / 13

19-6 Free Energy Change and Equilibrium

19-6 Free Energy Change and Equilibrium. Free Energy Change and Equilibrium. Condensation Equilibrium Vaporization. Relationship of Δ G ° to Δ G for Non-standard Conditions. 2 N 2 (g) + 3 H 2 (g) 2 NH 3 (g). Δ G = Δ H - T Δ S. Δ G ° = Δ H° - T Δ S°.

marc
Download Presentation

19-6 Free Energy Change and Equilibrium

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 19-6 Free Energy Change and Equilibrium

  2. Free Energy Change and Equilibrium Condensation Equilibrium Vaporization

  3. Relationship of ΔG° to ΔG for Non-standard Conditions 2 N2(g) + 3 H2(g) 2 NH3(g) ΔG = ΔH - TΔS ΔG° = ΔH° - TΔS° For ideal gases ΔH = ΔH° ΔG = ΔH° - TΔS

  4. qrev Vf = R ln ΔS = T Vi Pf Pi Vf = R ln = -R ln = R ln ΔS = Sf – Si Pi Pf Vi P P - R ln - R ln = S° - R ln P = S° S = S° 1 P° Relationship Between S and S° Vf qrev = -w = RT ln Vi

  5. 3 PN2PH2 ΔSrxn = 2 SNH3 – SN2 –3SH2+ Rln 2 PNH3 3 PN2PH2 ΔSrxn = ΔS°rxn + Rln 2 PNH3 N2(g) + 3 H2(g) 2 NH3(g) SN2= SN2 – Rln PN2 SH2 =SH2 – Rln PH2 SNH3 = SNH3 – Rln PNH3 ΔSrxn = 2(SNH3 – Rln PNH3) – (SN2 – Rln PN2) –3(SH2 – Rln PH2)

  6. 3 2 PN2PH2 ΔG = ΔH° - TΔS°rxn – TR ln 2 PNH3 2 PNH3 ΔG = ΔG° + RT ln 3 2 PN2PH2 3 2 PN2PH2 ΔSrxn = ΔS°rxn + Rln 2 PNH3 ΔG Under Non-standard Conditions ΔG = ΔH° - TΔS ΔG = ΔG° + RT ln Q

  7. If the reaction is at equilibrium then: ΔG = ΔG° + RT ln Keq= 0 ΔG and the Equilibrium Constant Keq ΔG = ΔG° + RT ln Q ΔG° = -RT ln Keq

  8. Criteria for Spontaneous Change Every chemical reaction consists of both a forward and a reverse reaction. The direction of spontaneous change is the direction in which the free energy decreases.

  9. Significance of the Magnitude of ΔG

  10. -ΔG° -ΔH° TΔS° ln Keq = = + RT RT RT -ΔH° ΔS° ln Keq = + RT R 19-7 ΔG° and Keq as Functions of Temperature ΔG° = ΔH° -TΔS° ΔG° = -RT ln Keq

  11. Van’t Hoff Equation If we evaluate this equation for a change in temperature: Keq2 -ΔH° ΔS° -ΔH° ΔS° - ln = + + RT2 R RT1 R Keq1 Keq2 1 1 -ΔH° - = ln T2 T1 R Keq1

  12. -ΔH° slope = R -ΔH° ΔS° ln Keq = + RT R Temperature Dependence of Keq Assume ΔH° and ΔS° do not vary significantly with temperature. -ΔH° = Rslope = -8.3145 J mol-1 K-1  2.2104 K = -1.8102 kJ mol-1

More Related