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Tarea 9 espectro electromagnético

Juan Pablo Arias Cod : 258134. Tarea 9 espectro electromagnético. Teoría. La energía en joule se expresa así: E(J) = h F F es la frecuencia del espectro electromagnético, h es la constante de plank

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Tarea 9 espectro electromagnético

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  1. Juan Pablo Arias Cod: 258134 Tarea 9espectro electromagnético

  2. Teoría • La energía en joule se expresa así: E(J) = h F F es la frecuencia del espectro electromagnético, h es la constante de plank • La frecuencia F es la relación entre la velocidad c de la luz en el vacio y la longitud de onda λ de dicho espectro: F = c/λ • Energía en electrón-voltio: E(eV) = (h c)/(λ qe) h= 6,6 X10^-34 J.s c= 3 X10^8 m/s qe= 1,6 X10^19 C

  3. Verde λ = 5000x 10^-10 m • Frecuencia F = 3x10^8 / 5000x10^-10 F = 6x10^14 • Energía en J E (J) = 6,6x10^-34 * 6x10^14 E (J) = 3,96x10^-19 • Energía en eV E (eV) = 3,96x10^-19 / 1,6x10^-19 E (eV) = 2,475 eV

  4. rojo λ = 6580x 10^-10 m • Frecuencia F = 3x10^8 / 6580x10^-10 F = 4,55x10^14 • Energía en J E (J) = 6,6x10^-34 * 4,55x10^14 E (J) = 3,003x10^-19 • Energía en eV E (eV) = 3,003x10^-19 / 1,6x10^-19 E (eV) = 1,87 eV

  5. naranja λ = 6000x 10^-10 m • Frecuencia F = 3x10^8 / 6000x10^-10 F = 5x10^14 • Energía en J E (J) = 6,6x10^-34 * 5x10^14 E (J) = 3,3x10^-19 • Energía en eV E (eV) = 3,3x10^-19 / 1,6x10^-19 E (eV) = 2,06 eV

  6. amarillo λ = 5800x 10^-10 m • Frecuencia F = 3x10^8 / 5800x10^-10 F = 5,172x10^14 • Energía en J E (J) = 6,6x10^-34 * 5,172x10^14 E (J) = 3,413x10^-19 • Energía en eV E (eV) = 3,413x10^-19 / 1,6x10^-19 E (eV) = 2,13 eV

  7. azul λ = 4700x 10^-10 m • Frecuencia F = 3x10^8 / 4700x10^-10 F = 6,382x10^14 • Energía en J E (J) = 6,6x10^-34 * 6,382x10^14 E (J) = 4,212x10^-19 • Energía en eV E (eV) = 4,212x10^-19 / 1,6x10^-19 E (eV) = 2,63 eV

  8. Violeta λ = 4150x 10^-10 m • Frecuencia F = 3x10^8 / 4150x10^-10 F = 7,228x10^14 • Energía en J E (J) = 6,6x10^-34 * 7,228x10^14 E (J) = 4,771x10^-19 • Energía en eV E (eV) = 4,212x10^-19 / 1,6x10^-19 E (eV) = 2,98 eV

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