360 likes | 539 Views
The Relational Model. What DB models exist?. Most widely current model: Relational Model Vendors: IBM DB2, Microsoft, Oracle, Sybase, etc… “Legacy systems” have older models E.g., IBM’s IMS ( hierarchical ), CODASYL network model Recent and future competitors:
E N D
What DB models exist? • Most widely current model: Relational Model • Vendors: IBM DB2, Microsoft, Oracle, Sybase, etc… • “Legacy systems” have older models • E.g., IBM’s IMS (hierarchical), CODASYL network model • Recent and future competitors: • object-oriented model: ObjectStore, Versant • Object-relational model: Oracle, DB2 • Semi-structured: XML • Integrated in all major relational database systems • Native XML database systems
Definitions • Relational Database: a set of relations • Relation: Consists of two parts: • Schema: specifies name of relation, plus a set of attributes, plus the domain/type of each attribute • E.g., Students(sid:string, name:string, login:string, faculty:string, gpa:real) • Instance: set of tuples (all tuples are distinct). • A relation can be seen as a table: • Column headers = attribute names, rows = tuples/records, columns/fields = attribute values • #Rows = cardinality • #Fields = degree / arity • If clear from context, we say instead of “instance of a relation” simply “relation” • Database Schema: collection of relation schemas
Example of Students Relation name sid gpa faculty Column headers = attributes login • All rows are distinct (set-oriented) • Rows are not ordered (a permutation of rows represents still the same table) • Columns are per definition not ordered but in practice we often assume a fixed order • with this, a single tuple can be represented as (53666, Bartoli, bartoli@cs, Science, 3.4) 53666 Bartoli bartoli@cs Science 3.4 53688 Chang chang@eecs Eng 3.2 53650 Chang chang@math Science 3.8 Cardinality = 3 Degree = 5 ...
Relational DDL and DML • Data Definition Language (DDL): defines the schema of a database • Data Manipulation Language (DML): “manipulates” the data, i.e., the instances of the relations • Insert, update, delete tuples • “Query” the relations: retrieve tuples that fulfill certain criteria (hence, often called “query language”) • The Relational Model offers simple and powerful querying of data with precise semantics independent of how data is stored or whether changes in the physical structure are made (physical data independence)
The SQL Query Language • Developed by IBM (system R) in the 1970s • Need for a standard since it is used by many vendors • Standards: • SQL-86 • … • SQL-99 / SQL3 (adds object-relational features) • SQL:2003 (adds XML features)
SQL Data Types • All attributes must have a data type. • SQL supports several basic data types • Character and string types • CHAR(n) denotes a character string of fixed length (containing trailing blanks for padding if necessary). • VARCHAR(n) denotes a string of up to n characters (between 0 and n characters). • SQL permits reasonable coercion between values of character-string types • Integer Types • INT or INTEGER (names are synonyms) • SHORTINT
Data Types (contd.) • Floating point numbers • FLOAT or REAL (names are synonyms) • DOUBLE PRECISION • DECIMAL(n,d): real number with fixed decimal point. Value consists of n digits, with the decimal point d positions from the right. • Dates and time: • DATE: has the form ‘YYYY-MM-DD’ • TIME: has the form ‘15:00:02’ or ‘15:00:02.5’ • May be compared and converted to string types • Bit strings • User defined domains • New name for a data type • Possibility to define restrictions on values of domain (< 10)
Defines all attributes of the relation The type/domain of each attribute is specified DBMS enforce correct type whenever a tuple is added or modified SQL is case insensitive It is possible to define default values Special NULL value: ‘unknown’ CREATE TABLE Students (sid CHAR(20), name VARCHAR2(20), login CHAR(10), faculty VARCHAR(20), gpa REAL DEFAULT 0.0) CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2)) Data Definition: Table Creation
Data Definition: Destroying and Altering Relations • Destroys the relation Students. The schema information and the tuples are deleted. DROP TABLE Students ALTER TABLE Students ADD COLUMN firstYear:integer • The schema of students is altered by adding a new field; every existing tuple in the current instance is extended with a null value in the new field.
Data Manipulation: insert, delete, update • Insert a single tuple using: • Can delete all tuples satisfying some condition • Can update all tuples satisfying some condition INSERT INTO Students (sid,name,login,faculty,gpa) VALUES(53688,’Chang’,’cheng@eecs’,’Eng’,3.2) INSERT INTO Students (sid,name,login,faculty) VALUES(53688,’Chang’,NULL,’Eng’) DELETE FROM Students WHERE name = ‘Chang’ UPDATE Students SET gpa = 3.4 WHERE sid = 53688
Querying the Data • Find the names and gpa of all students with gpa less than 3.5 SELECT name, gpa FROM Students WHERE gpa < 3.5 name sid gpa faculty login name gpa 53666 Bartoli bartoli@cs Science 3.4 53688 Chang chang@eecs Eng 3.2 53650 Chang chang@math Science 3.8 Bartoli 3.4 Chang 3.2
Integrity Constraints (ICs) • Integrity Constraints must be true for any instance of the database; • e.g., domain constraints • ICs are specified when schema is defined • ICs are checked when relations are modified • A legal instance of a relation is one that satisfies all specified ICs. • DBMS should not allow illegal instances • If DBMS checks ICs, stored data is more faithful to real-world meaning (also checks for entry errors) • Of course, DBMS can only check what is specified in the schema
Primary Key Constraints • A set of fields is a key for a relation if • No two distinct tuples can have same values in all key fields, and • This is not true for any subset of the key. • If there are two or more keys, one of the candidates is chosen to be the primary key. • The primary key attributes of a tuple may not be NULL. • A set of fields that contains a subset of fields fulfilling the key constraint is called a superkey • E.g. sid is a key for Students. (What about name?). The set (sid,gpa) is a superkey
Possibly many candidate keys exist, one of which is chosen as the primary key Each student has a unique id. For a given student and course, there is a single grade; further, no two students in a course receive the same grade Application dependent Defined carelessly, an IC can prevent the storage of database instances that arise in practice! CREATE TABLE Students (sid CHAR(20) PRIMARY KEY, name VARCHAR2(20), … CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2), PRIMARY KEY (sid,cid), UNIQUE (cid,grade)) Primary and Candidate Keys in SQL
Foreign Key • Foreign Key: Set of fields in one relation that is used to “refer” to a tuple in another relation. • Must correspond to the primary key of the second relation. • Represents a “logical pointer”. • Examples • in relation Enrolled, sid is a foreign key referring to Students: Students(sid:CHAR(20),name:VARCHAR(20),login:CHAR(10), faculty:VARCHAR(20), gpa:REAL) Enrolled(sid:CHAR(20),cid:CAHR(20),grade:CHAR(2))
Referential Integrity • Foreign Key Constraint: the foreign key value of a tuple must represent an existing tuple in the referred relation • Enrollment may only contain a tuple of a student who exists in the Students relation • If all foreign key constraints are enforced, referential integrity is achieved, i.e., no dangling references
Foreign Keys in SQL CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2), PRIMARY KEY (sid,cid) FOREIGN KEY (sid) REFERENCES Students) • Only students listed in the Students relation should be allowed to enroll for courses sid cid grade 53666 Topology112 C 53666 Reggae203 B 53650 Topology112 A 53668 History105 B name sid gpa faculty login 53666 Bartoli bartoli@cs Science 3.4 53688 Chang chang@eecs Eng 3.2 53650 Chang chang@math Science 3.8
Enforcing Referential Integrity • An Enrolled tuple with a sid is inserted such that no tuple with this sid exists in Students • Disallow insertion • A Students tuple is deleted • Delete all Enrolled tuples that refer to it • Disallow the deletion of a Students tuple to which Enrolled tuples point • Set sid in Enrolled tuples that refer to it to “default sid” • (in SQL set sid in Enrolled tuples that refer to it to NULL value) • The primary key of a Students tuple is changed • Update the sid of all Enrolled tuples that refer to the original value • Further options similar to delete
SQL standard supports all 4 options on deletes and updates Default is NO ACTION delete/update is rejected CASCADE also delete/update all tuples that refer to the deleted/updated tuple SET NULL / SET DEFAULT Set foreign key value of referencing tuple to NULL / given default CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2), PRIMARY KEY (sid,cid) FOREIGN KEY (sid) REFERENCES Students ON DELETE CASCADE ON UPDATE SET NULL) Referential Integrity in SQL/92
Where do ICs come from? • ICs are based on the semantics of the real-world enterprise that is being described in the database relations • We can check a database instance to see if an IC is violated, but we can NEVER infer that an IC is true by looking at an instance • An IC is a statement about all possible instances • For example, we might think that the student name is a key because in a given instance there do not exist two tuples with the same name; but it might happen in the future. • Key and foreign key ICs are the most common; more general ICs supported, too. (Discussed later in the course)
Entity sets to tables Employees(eid, name, salary) CREATE TABLE Employees (eid CHAR(11), name VARCHAR(20), salary REAL, PRIMARY KEY (eid)) Departments(did, dname, budget) CREATE TABLE Departments (did INTEGER, dname CHAR(20), budget REAL, PRIMARY KEY (did)) Logical Design: ER to Relational name eid salary Employees Departments budget did dname
Map relationship set to table. Attributes of the table must include Keys for each participating entity set (as foreign keys) This set of attributes forms the key for the relation All descriptive attributes Works_in(eid, did, since) CREATE TABLE Works_In (eid CHAR(11), did INTEGER, since DATE, PRIMARY KEY (eid,did), FOREIGN KEY (eid) REFERENCES Employees, FOREIGN KEY (did) REFERENCES Departments) Many-to-many Relationship Sets name eid salary Employees since Works_in Departments budget did dname
Alternative 1: map relationship set to table Many-one from entity set E1 to entity set E2: key of E1 i.e., key of entity-set with the key constraint is the key for the new relationship table (did is now the key) One-one: key of either entity set Separate tables for entity sets (Employees and Departments) Manages(eid, did, since) CREATE TABLE Manages (eid CHAR(11), did INTEGER, since DATE, PRIMARY KEY (did), FOREIGN KEY (eid) REFERENCES Employees, FOREIGN KEY (did) REFERENCES Departments) Relationships Sets with Key Constraints name eid salary Employees since Manages Departments budget did dname
Alternative II: include relationship set in table of the entity set with the key constraint Possible because there is at most one relationship per entity Not useful if many entities do not have a relationship (wasted space, many not filled values) DepartmentsM(did, dname, budget, eidmgr, since) CREATE TABLE DepartmentsM (did INTEGER, dname CHAR(20), budget REAL, eidmgr CHAR(11), since DATE, PRIMARY KEY (did), FOREIGN KEY (eidmgr) REFERENCES EMPLOYEES(eid)) Relationships Sets with Key Constraints (contd.) name eid salary Employees since Manages Departments budget did dname
Relationship Sets with Participation Constraints and Key Constraints • Include relationship set in table of the entity set with the key constraint and the participation constraint • We can capture participation constraints involving one entity set in a binary relationship if it also has a key constraint, but little else (at least within the table definitions) • DepartmentsM(did, dname, budget, eidmgr, since) CREATE TABLE DepartmentsM (did INTEGER, dname CHAR(20), budget REAL, eidmgr CHAR(11) NOT NULL, since DATE, PRIMARY KEY (did), FOREIGN KEY (eidmgr) REFERENCES EMPLOYEES(eid)) name eid salary Employees since Manages Departments budget did dname
Renaming • In the case the keys of the participating entity sets have the same names we must rename attributes accordingly • Reports_To(super-eid, sub-eid) CREATE TABLE Reports_To (supervisor_eid CHAR(11), subordinate_eid CHAR(11), PRIMARY KEY (supervisor_eid, subordinate_eid), FOREIGN KEY (supervisor_eid) REFERENCES Employees(eid), FOREIGN KEY (subordinate_eid) REFERENCES Employees(eid)) name eid salary Employees supervisor subordinate Reports_To
Weak entity set and identifying relationship set are translated into a single table When the owner entity is deleted, all owned weak entities must also be deleted Translating Weak Entity Sets • Dependants_Policy(pname, dob, cost, eid) CREATE TABLE Dependants_Policy (pname CHAR(20), dob DATE, cost REAL, eid CHAR(11), PRIMARY KEY (pname,eid), FOREIGN KEY (eid) REFERENCES Employees, ON DELETE CASCADE) name eid salary Employees cost Policy Dependants pname dateofbirth
Translating ISA Hierarchies • General Approach: distribute information among relations • Relation of superclass stores the general attributes and defines key • Relations of subclasses have key of superclass and addit. attributes • when a tuple in super-relation is deleted, corresponding tuples in sub-relation must be deleted • Employees(eid, name, salary) • Contract_Emps(contract_id,eid) CREATE TABLE Employees (eid CHAR(20), name CHAR(20),salary REAL, PRIMARY KEY (ssn)) CREATE TABLE Contract_Emps (contract_id INTEGER, eid CHAR(11), PRIMARY KEY (eid), FOREIGN KEY (eid) REFERENCES Employees, ON DELETE CASCADE) name eid salary Employees hours_worked Contract_id hourly_wages ISA Hourly_Emps Contract_Emps
Translating ISA Hierarchies (contd.) • Employees(eid, name, salary) • Hourly_Emps(eid,name,salary, hourly_wages,hours_worked) • Contract_Emps(eid, name, salary,contract_id) CREATE TABLE Employees (eid CHAR(20) PRIMARY KEY, name CHAR(20),salary REAL) CREATE TABLE Hourly_Emps (eid CHAR(20) PRIMARY KEY, name CHAR(20),salary REAL, hourly_wages REAL, hours_worked REAL) CREATE TABLE Contract_Emps (eid CHAR(20) PRIMARY KEY, name CHAR(20),salary REAL, contract_id INTEGER) • Object-oriented approach: • Sub-classes have all attributes; • if an entity is in a sub-class it does not appear in the super-class relation; • Pro/Contra: + A query asking for all hourly employees only has to go to one relation (in general approach it has to read two relations) - Query on general attributes of all employees has to read all three tables - If an entity is both Hourly_emps and Contract_emps, name and salary are stored twice => undesired redundancy
Last Alternative: one big relation Create only one relation for the root entity set with all attributes found anywhere in its network of subclasses. Put NULL in attributes not relevant to a given entity Translating ISA Hierarchies (contd.) • Employees(eid,name,salary, hourly_wages,hours_worked, contract_id) CREATE TABLE Employees (eid CHAR(20), name CHAR(20), salary REAL, hourly_wages REAL, hourly_worked REAL, contract_id INTEGER, PRIMARY KEY (eid))
Translating Aggregation • Key constraint from Projects to Departments • Projects(pid, started_on, pbudget, did, since) • No Sponsors • Monitors(pid, eid, until) • No key constraints • Projects(pid,started_on,pbudget) • Departments(did,dname,budget) • Employees(eid,name,salary) • Sponsors(pid,did,since) • Monitors(pid,did,eid,until) • Key constraint from Sponsors to Employees • Sponsors(pid,did,eid,since,until) • No Monitors eid name Employees salary Monitors until since Started_on did dname budget pid pbudget Departments Sponsors Projects
Relational Model: Summary • A tabular representation of data • Simple and intuitive, currently the most widely used model. • Integrity constraints can be specified based on application semantics (up to a certain degree). DBMS checks for violations • Two important ICs : primary and foreign keys • In addition, we always have domain constraints • Powerful and natural query languages exist • Rules to translate ER to relational model
Review: Binary vs. Ternary name pname ssn dob lot • Putting any constraints in upper picture: • Key constraint on Policies (to guarantee that each policy only owned by one employee), would also mean that the policy can only cover one dependent • Constraints of lower picture: • Each dependant determined by one policy • Each policy is owned by one employee Employees covers Dependants pid cost Policies pname dob name ssn lot Dependants Employees beneficiary purchaser cost Policies pid
Key constraints allow us to combine Purchaser with Policies and Beneficiary with Dependants Participation constraints lead to NOT NULL constraints (or primary key in case of weak entity) What if policy is a weak entity? Binary vs. Ternary • Policies(pid, cost, eid) • Dependants(pname, dob, pid) CREATE TABLE Policies (pid INTEGER, cost REAL, eid CHAR(11) NOT NULL, PRIMARY KEY (pid), FOREIGN KEY (eid) REFERENCES Employees ON DELETE CASCADE) CREATE TABLE Dependants (pname CHAR(20), dob DATE, pid INTEGER, PRIMARY KEY (pname,pid), FOREIGN KEY (pid) REFERENCES Policies, ON DELETE CASCADE)