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Keys to the Study of Chemistry

Keys to the Study of Chemistry. Ashton T. Griffin Wayne Community College Chapter 1.1-1.6 in Silberberg 5 th and 6 th editions. Goals & Objectives . The student will be able to identify the name and symbol of the first 36 elements on the periodic table. (I-1)

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Keys to the Study of Chemistry

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  1. Keys to the Study of Chemistry • Ashton T. Griffin • Wayne Community College • Chapter 1.1-1.6 in Silberberg 5th and 6th editions.

  2. Goals & Objectives • The student will be able to identify the name and symbol of the first 36 elements on the periodic table. (I-1) • The student will understand the common units of length, volume, mass, and temperature and their numerical prefixes. (1.5)

  3. Goals & Objectives • The student will understand the meaning of uncertainty in measurements and the use of significant figures and rounding. (1.6) • The student will understand the distinction between accuracy and precision and between systematic and random error. (1.6)

  4. Master these Skills • The student will be able to: • Use conversion factors in calculations (1.4; SP 1.3-1.5) • Find the density from mass and volume (SP 1.6) • Convert between the Kelvin, Celsius, and Fahrenheit temperature scales (SP 1.7)

  5. Master these Skills • The student will be able to: • Determine the number of significant figures (SP 1.8) and rounding to the correct number of digits. (SP 1.9)

  6. Chemistry Chemistry is the study of matter, its properties, the changes that matter undergoes, and the energy associated with these changes.

  7. Definitions Matter anything that has both mass and volume - the “stuff” of the universe: books, planets, trees, professors, students Composition the types and amounts of simpler substances that make up a sample of matter Properties the characteristics that give each substance a unique identity

  8. Physical Properties properties a substance shows by itself without interacting with another substance - color, melting point, boiling point, density Chemical Properties properties a substance shows as it interacts with, or transforms into, other substances - flammability, corrosiveness

  9. Figure 1.1 The distinction between physical and chemical change.

  10. Table 1.1 Some Characteristic Properties of Copper

  11. Elements • The simplest forms of matter • Cannot be separated by chemical means into simpler stable substances • Represented by symbols on the Periodic Table • Learn the names and symbols for first 36 elements (I-1)

  12. The States of Matter A solid has a fixed shape and volume. Solids may be hard or soft, rigid or flexible. A liquid has a varying shape that conforms to the shape of the container, but a fixed volume. A liquid has an upper surface. A gas has no fixed shape or volume and therefore does not have a surface.

  13. Figure 1.2 The physical states of matter.

  14. Temperature and Change of State • A change of state is a physical change. • Physical form changes, composition does not. • Changes in physical state are reversible • by changing the temperature. • A chemical change cannot simply be reversed by a change in temperature.

  15. PROBLEM: Decide whether each of the following processes is primarily a physical or a chemical change, and explain briefly: (a) Frost forms as the temperature drops on a humid winter night. (b) A cornstalk grows from a seed that is watered and fertilized. (c) A match ignites to form ash and a mixture of gases. (d) Perspiration evaporates when you relax after jogging. (e) A silver fork tarnishes slowly in air. PLAN: “Does the substance change composition or just change form?” Sample Problem 1.2 Distinguishing Between Physical and Chemical Change

  16. Sample Problem 1.2 SOLUTION: (a) Frost forms as the temperature drops on a humid winter night. physical change (b) A cornstalk grows from a seed that is watered and fertilized. chemical change (c) A match ignites to form ash and a mixture of gases. chemical change (d) Perspiration evaporates when you relax after jogging. physical change (e) A silver fork tarnishes slowly in air. chemical change

  17. Energy in Chemistry Energy is the ability to do work. Potential Energy is energy due to the position of an object. Kinetic Energy is energy due to the movement of an object. Total Energy = Potential Energy + Kinetic Energy

  18. Energy Changes Lower energy states are more stable and are favored over higher energy states. Energy is neither created nor destroyed – it is conserved – and can be converted from one form to another.

  19. Observations Natural phenomena and measured events; can be stated as a natural law if universally consistent. Hypothesis Tentative proposal that explains observations. Hypothesis is revised if experimental results do not support it. Procedure to test hypothesis; measures one variable at a time. Experiment Set of conceptual assumptions that explains data from accumulated experiments; predicts related phenomena. Model (Theory) Model is altered if predicted events do not support it. Further Experiment Tests predictions based on model Figure 1.6 The scientific approach to understanding nature.

  20. 350 mi 50 mi = or 50 mi.h-1 7 h 1 h Chemical Problem Solving • All measured quantities consist of • a number and a unit. • Units are manipulated like numbers: • 3 ft x 4 ft = 12 ft2

  21. 1 mi 5280 ft 5280 ft 5280 ft Conversion Factors A conversion factoris a ratio of equivalent quantities used to express a quantity in different units. The relationship 1 mi = 5280 ft gives us the conversion factor: = = 1

  22. PROBLEM: The height of the Angel Falls is 3212 ft. Express this quantity in miles (mi) if 1 mi = 5280 ft. PLAN: Set up the conversion factor so that ft will cancel and the answer will be in mi. 1 mi 5280 ft A conversion factor is chosen and set up so that all units cancel except those required for the answer. SOLUTION: 3212 ft x = 0.6083 mi

  23. Clarify the known and unknown. Suggest steps from known to unknown. Prepare a visual summary of steps that includes conversion factors, equations, known variables. Systematic Approach to Solving Chemistry Problems • State Problem • Plan • Solution • Check • Comment • Follow-up Problem

  24. PROBLEM: To wire your stereo equipment, you need 325 centimeters (cm) of speaker wire that sells for $0.15/ft. What is the price of the wire? PLAN: We know the length (in cm) of wire and cost per length ($/ft). We have to convert cm to inches and inches to feet. Then we can find the cost for the length in feet. length (cm) of wire length (in) of wire length (ft) of wire Price ($) of wire Sample Problem 1.3 Converting Units of Length 2.54 cm = 1 in 12 in = 1 ft 1 ft = $0.15

  25. = 325 cm x = 128 in = 128 in x = 10.7 ft x = 10.7 ft 1 in 2.54 cm $ 0.15 1 ft 1 ft 12 in Sample Problem 1.3 SOLUTION: Length (in) = length (cm) x conversion factor Length (ft) = length (in) x conversion factor Price ($) = length (ft) x conversion factor = $ 1.60

  26. Table 1. 2 SI Base Units

  27. Units -- Metric System • Mass kilogram(kg), gram(g) • Length meter(m), centimeter(cm) • Volume cubic meter(m3), cubic centimeter (cm3) liter(L) = 1000 cm3 (exact) milliliter(mL) = 1 cm3 (exact) • Time second(s) • Temperature Kelvin(K) Celsius (C)

  28. Additional SI Units • Current – Ampere • Amount of Substance – Mole • Luminous Intensity – Candela • Four of these units are of particular interest to chemist.

  29. The Second • Initially the second was tied to the Earth’s rotation. 1/86,400th of the mean solar day. • In 1967, the second was based on the cesium-133 atomic clock.

  30. The Meter • In 1791, the meter was defined to be one ten-millionth of the length of the meridian passing through Paris from the equator to the North Pole. • In 1889, a platinum-iridium bar was inscribed with two lines – this became the standard for the meter.

  31. The Meter (continued) • In 1960, the meter was based on the wavelength of krypton-86 radiation. • Finally in 1983, the meter was re-defined as the length traveled by light in exactly 1/299,792,458 of a second.

  32. The Kilogram • In 1799, a platinum-iridium cylinder was fabricated to represent the mass of a cubic deciliter of water at 4 C. In new standard was created in 1879. Due to the changing nature its mass, it was suggested in 2005 that the kilogram be redefined in terms of “fixed constants of nature”.

  33. The Kilogram Standard

  34. The Mole • Since the 1960’s, the mole has been based on the number of atoms in 12.0 g of carbon-12 or 6.022 x 1023 atoms. • New attempts to define the mole include using a new standard Si-28. • New attempts will continue.

  35. Table 1.3 Common Decimal Prefixes Used with SI Units

  36. Units-- Metric System • Use numerical prefixes for larger or smaller units: Mega (M) 1000000 times unit (106) kilo (k) 1000 times unit (103) centi (c) 0.01 times unit (10-2) milli (m) 0.001 times unit (10-3) Micro (µ) 0.000001 times unit (10-6)

  37. Table 1.4 Common SI-English Equivalent Quantities

  38. Figure 1.8 Common laboratory volumetric glassware.

  39. PROBLEM: A graduated cylinder contains 19.9 mL of water. When a small piece of galena, an ore of lead, is added, it sinks and the volume increases to 24.5 mL. What is the volume of the piece of galena in cm3 and in L? volume (mL) before and after subtract volume (mL) of galena PLAN: The volume of the galena is equal to the difference in the volume of the water before and after the addition. volume (cm3) of galena volume (L) of galena Sample Problem 1.4 Converting Units of Volume 1 mL = 1 cm3 1 mL = 10-3 L

  40. 4.6 mL x 4.6 mL x 1 cm3 1 mL 10-3 L 1 mL Sample Problem 1.4 SOLUTION: (24.5 - 19.9) mL = volume of galena = 4.6 mL = 4.6 cm3 = 4.6 x 10-3 L

  41. PROBLEM: Many international computer communications are carried out by optical fibers in cables laid along the ocean floor. If one strand of optical fiber weighs 1.19 x 10-3 lb/m, what is the mass (in kg) of a cable made of six strands of optical fiber, each long enough to link New York and Paris (8.94 x 103 km)? PLAN: The sequence of steps may vary but essentially we need to find the length of the entire cable and convert it to mass. length (km) of fiber length (m) of fiber mass (lb) of fiber Mass (kg) of cable mass (lb) of cable Sample Problem 1.5 Converting Units of Mass 1 km = 103 m 1 m = 1.19 x 10-3 lb 2.205 lb = 1 kg 6 fibers = 1 cable

  42. 8.84 x 103 km x = 8.84 x 106 m 1.19 x 10-3 lb 1 m 1.05 x 104 lb 1 fiber 6.30 x 104 lb 1 cable 8.84 x 106 m x = 1.05 x 104 lb 103 m 1 km 1 kg 2.205 lb 6 fibers 1 cable x x = 6.30 x 104 lb/cable Sample Problem 1.5 SOLUTION: = 2.86 x 104 kg/cable

  43. Units -- Metric System • Numerical Prefixes: • 12.5 m = _______ cm • 1.35 kg = _______ g • 0.0256 mm = _______ µm • 89.7 megahertz = _______ hertz (1 hertz = 1 cycle per second)

  44. Derived Quantities • Frequency (cycles/s, hertz) • Density (mass/volume, g/cm3) • Speed (distance/time, m/s) • Acceleration (distance/(time)2, m/s2) • Force (mass x acceleration, kg•m/s2, newton) • Pressure (force/area, kg/(m•s2), pascal) • Energy (force x distance, kg•m2/s2, joule)

  45. Figure 1.9 Some interesting quantities of length (A), volume (B), and mass (C).

  46. density = mass volume Density At a given temperature and pressure, the density of a substance is a characteristic physical property and has a specific value.

  47. Table 1.5 Densities of Some Common Substances* *At room temperature (20°C) and normal atmospheric pressure (1atm).

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