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Unit 2 PPA2 Preparation Of A Simple Ester. Preparation Of A Simple Ester (Unit 2 PPA 2). The aim of the experiment is to prepare the ester ethyl ethanoate from ethanol and ethanoic acid. What kind of reaction occurs when an alcohol and carboxylic acid react to form an ester?.
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Unit 2 PPA2 Preparation Of A Simple Ester
Preparation Of A Simple Ester (Unit 2 PPA 2) The aim of the experiment is to prepare the ester ethyl ethanoate from ethanol and ethanoic acid. . What kind of reaction occurs when an alcohol and carboxylic acid react to form an ester? Condensation reaction.
PREPARATION OF A SIMPLE ESTER (Unit 2 PPA 2) The diagram below shows the apparatus used in the laboratory preparation of ethyl ethanoate. Why is the mixture heated using a hot water bath and not directly with a Bunsen flame? The reactants and products are highly flammable. This reduces the risk of them catching fire.
PREPARATION OF A SIMPLE ESTER (Unit 2 PPA 2) The diagram below shows the apparatus used in the laboratory preparation of ethyl ethanoate. What is the purpose of the damp paper towel? This acts as a condenser and stops loss of the volatile reactants and product.
PREPARATION OF A SIMPLE ESTER (Unit 2 PPA 2) The diagram below shows the apparatus used in the laboratory preparation of ethyl ethanoate. What is the purpose of the concentrated sulphuric acid? This acts as a catalyst and gives a higher yield of ester by stopping the reverse reaction.
PREPARATION OF A SIMPLE ESTER (Unit 2 PPA 2) At the end of the reaction the contents of the boiling tube and poured into a beaker containing sodium hydrogen-carbonate solution. What two things would you see happening when this occurs? Bubbles of carbon dioxide gas are given off and an oily layer of the (insoluble) ester appears on top of the aqueous solution.
PREPARATION OF A SIMPLE ESTER (Unit 2 PPA 2) A student reacted 2.30g of ethanol with an excess of ethanoic acid. The mass of ethyl ethanoate obtained was 2.68g. Using the balanced equation for the reaction shown below, calculate the percentage yield. C2H5OH + CH3COOH C2H5OOCCH3 + H2O 1 mol 1mol at 100% yield 46g 88g at 100% yield 2.3g 4.4g at 100% yield Percentage yield = 2.68 / 4.4 x 100 = 60.9%