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y (4260) To what extent a charmonium? International workshop on heavy quarkonium June 27 th , 2006. Felipe J. Llanes-Estrada Univ. Complutense Madrid. 1. Model Hamiltonian:. Treat physical gluon exchange in perturbation theory. Take V as a classical Cornell potential between
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y(4260) To what extent a charmonium? International workshop on heavy quarkonium June 27th, 2006 Felipe J. Llanes-Estrada Univ. Complutense Madrid 1
Model Hamiltonian: Treat physical gluon exchange in perturbation theory Take V as a classical Cornell potential between charge densities 2
Trigonometric or hyperbolic Bogoliubov rotation generates a quasiparticle mass gap 4
Fock space expansion Collaborators:S. Cotanch, E. Swanson, A. Szczepaniak, I. General, Ping Wang 7
IR Behavior of a connected, fully amputated Yang-Mills Green’s function in Landau gauge with 2n ghost and m gluon legs Alkofer, Fischer, Llanes-Estrada, PLB05 8
Spectrum In quark sector Llanes-Estrada,Szczepaniak,Swanson, Cotanch, PRC04 9
y(4260): new vector state from Babar Clearly contains cc and is a vector 11
With the 4s assignment the c,b spectra lock Figure courtesy of J. Rosner 12
Not apparent In R!! 13
Look at the world upside-down No one can miss the y(4260) now 14
Interference fit: Calculate DD, DsDs production Form factors including y(4040) and/not y(4260) (+) y(4160), y(4440) (-) Theoretical inspiration? Godfrey and Isgur rpp (+) rDpp (-) 15
16 Of course, a lot of it should proceed by intermediate D*(Cornell prd81)
Interference fit increased Gee widths Better agreement with theory! Gee(4040) up to 1.5 keV from 0.75keV (1.7-1.9 keV theory) Gee(4260) Theory: 1keV (being 4S) would give a (probably unnoticed) bump in R At the level of 0.5 keV, wiped out by Interference 17
The Cornell coupled channel approach 18
“String breaking” in lattice computations SESAME Collaboration G. Bali et al prd2005 1) Softer potential (levels closer together) 2) Does not support resonances above threshold 19
Test 0: When R is remeasured, try interference fit (allow three free phases for y[4160,4260,4440] ) Very likely, larger lepton widths 20
J/y pp width seems too large for the 4S No good theory: resort to analogy G[Y(4S) ppY(1S)]= 1.8(4)keV Babar hep-ex/060431 G[Y(2S) ppY(1S)]= 7 keV G[y(2S) ppy(1S)]= 90 keV We would expect: G[y(4S) ppy(1S)]= 20-25 keV 21
Total width G(y(4260))=88(25) MeV Gee B(J/ypp) =5.5(10)(8) eV Taking the max. acceptable with interference 1keV G(y(4260) J/ypp) = 485 keV A factor of 20 off !! 22
Fock Space Expansion: | qq > + | qqqq > + | gg > + | qqg > + | qqqqqq > . . . Whatever is not forbidden, is mandatory: “This state is an (X) state” misleading when strong mixing. 23
Molecules with closed flavor mesons unlikely (Explanation by E. Ribeiro 1980) = 0 (color factor) repulsive attractive 24
A usual misquote In theory papers: f0 J/y not in Babar nor Cleo 25
Test 1: to distinguish charmonium from cscs tetraquark FLE prd05 26
Distinguishing conventional from hybrid Charmonium is more subtle Test 2: Counting rules for inclusive production in e-e+ collider Limit of the cross section as x 1 x= Ey(4260)/Ebeam cc: (1-x) ccg: (1-x)3 J.Gunion PLB79 x 1 28
Test 3: counting rules for exclusive double charmonium production Bodwin, Lee and Braaten prl2003 e-e+ J/y y(4260) r = 2mc/Ebeam Fixed angle production when r 0 ds/dx constant for cc 1/r2 for ccg 29
Test 4: distinguish the wavefunctions Franck-Condon principle (1925) Molecular transitions between two adiabatic levels: nuclei are not affected by the fast electronic jump. 30
Consider relative momentum distribution of DD subsystem in DDp final state 32
35 The hybrid p distribution has no shoulders
To test the idea with a sharper signal: Belle run at the Y(5S) Test 5: Look at the momentum distribution of BB in the BBp final state. Test 6: search for a new vector state in Ypp (to have a supernumerary matching the 4260) between the 4S and 5S. (W.S. Hou) 36
37 New state should be named y(4260) Interference fits in R will lead to increased lepton widths and could hide the 4s state GJ/ypp has no credible explanation DsDs spectrum to distinguish 4q from 2q Counting rules apply to disentangle qq,qqg Locate nodes of the wavefunction by examining final state momentum distribution. Conclusions A conventional state y(4s) could be feeding a part of the signal at 4260 MeV
y(4260) To what extent a charmonium? International workshop on heavy quarkonium June 27th, 2006 Felipe J. Llanes-Estrada Univ. Complutense Madrid 38