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Use lists, tables and tree diagrams to represent sample spaces. I can use the Fundamental counting Principle to count outcomes. Lesson 12.1. experiment. outcomes. outcome. trial. event. experiment. sample space. tree diagram. H H. T T. T H. H T. H. T. H. H H. H H. H T. H. H.
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Use lists, tables and tree diagrams to represent sample spaces • I can use the Fundamental counting Principle to count outcomes Lesson 12.1
experiment outcomes outcome trial event experiment sample space tree diagram
H H T T T H H T H T H H H H H H T H H H T T T T T T H T H H T T T T
H T 1 H1 T1 H 1 H 2 H 3 H 4 H 5 H 6 T 1 T 2 T 3 T 4 T 5 T 6 2 H2 T2 3 H3 T3 4 H4 T4 5 H5 T5 6 H6 T6
kids with cheese and pickles P C NP K P NC NP 12 different orders possible P C R NP NC P 3 ⦁ 2 ⦁ 2 = 12 NP P C D NP NC P NP
960,000 10 ⦁ 2 ⦁ 12 ⦁ 5 ⦁ 20 ⦁ 20 ⦁ 2 =
83,160 11 ⦁ 7 ⦁ 5 ⦁ 3 ⦁ 6 ⦁ 4 ⦁ 3 =
ASSIGNMENT 12-1 worksheet
I can use permutations with probability • I can use combinations with probability Lesson 12.2
n! 4 ⦁ 3 ⦁ 2 ⦁ 1 = 24 = 3,628,800 • 10 ⦁ 9 ⦁ 8 ⦁ 7⦁ 6 ⦁ 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 10! = • 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 = 120 5! =
order n Pr n! (n – r)! 5! • 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 5 P2 = = 20 = • 3 ⦁ 2 ⦁ 1 (5 – 2)! 6! • 6 ⦁ 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 6 P4 = = 360 = • 2 ⦁ 1 (6 – 4)!
10 P4 = 5040 8 P3 = 336
order n! n Cr r!(n – r)! • 10 ⦁ 9 ⦁ 8 ⦁ 7 ⦁ 6 ⦁ 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 10! 10 C4 = = • 4 ⦁ 3 ⦁ 2 ⦁ 1 • ⦁ 6 ⦁ 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 4! (10 – 4)! 5040 = 210 24
5! • 5 ⦁ 4 ⦁ 3 ⦁ 2 ⦁ 1 5 C 2 = = 2! (5 – 2)! • 2 ⦁ 1 • ⦁ 3 ⦁ 2 ⦁ 1 20 = 10 2
336 8 P3 = 10 5 C3 = 60 C 5 = 5,461,512 4845 20 C4 = 24 4 P4 =
1 1 = 20 C 6 38,760 1 1 = 380 20 P 2
1 1 = 65,780 26 C 5 1 1 = 870 30 P 2
ASSIGNMENT 12-2 worksheet
I can solve problems involving geometric probability • I can solve problems involving sectors and segments of circles Lesson 12.3
chance Area of B Total area
Area of square 4 = = 0.14 Total area 28
Area of shaded 48 = = 0.48 Total area 100
80 P(red) = 360 = 0.222
120 P(blue) = 360 = 0.333
π(22) = 4π – π(12) = 1π = 3π (area of white region) π(32) = 9π (area of target) 3π P(white) = = 0.333 9π
π(62) = 36π – π(32) = 9π = 27π (area of blue region) π(62) = 36π (area of target) 27π P(blue) = = 0.75 36π
ASSIGNMENT 12-3 worksheet
I can find the probabilities of independent and dependent events • I can find the probability of events given the occurrence of other events Lesson 12.4
2 or more does not affects
independent dependent independent
independent dependent
P(A and B) = P(A) ⦁ P(B) 1 1 1 1 1 36 6 6 6 6 ⦁ =
1 1 1 1 1 3 3 3 3 9 ⦁ =
P(regular 1st and 2nd) ⦁ = 8 7 56 156 13 12
⦁ = ⦁ = 6 30 5 3 1 3 90 90 10 10 9 9 TV TV TV TV TV TV C V V V
ASSIGNMENT 12-4 worksheet
I can find the probabilities of events using two-way frequency tables Lesson 12.5
20 10 12 18 30 P(male) = 20/30 P(female) = 10/30 P(11th) = 12/30 P(12th) = 18/30
20 10 12 18 30 4/12 6/10 12/18 0
44 25 69 91 59 32 84 160 76 69 76
43.1% 15.6% 56.9% 20% 36.9% 100% 47.5% 52.5% 47.5% of 285 0.475(285) ≈ 135 students ≈ 0.579 44/76
ASSIGNMENT 12-5 worksheet
I can find probabilities of events that are mutually exclusive and events that are not mutually exclusive Lesson 12.6
mutually exclusive yes no no
no no no yes
P(A or B) = P(A) + P(B) 22 10 12 + = 35 35 35 35
+ = 41 10 15 4 16 10 6 36 80 36 80 80 80 36 + + =
P(A or B) = P(A) + P(B) – P(A and B) P(H or K) = –P(H and K) P(H) + P(K) 16 13 1 4 + – = 52 52 52 52