1 / 3

AOX BOX by the definition of an angle bisector.

In the diagram, radius OX bisects AOB . What can you conclude?. AOX BOX by the definition of an angle bisector. AX BX because congruent central angles have congruent chords. AX BX because congruent chords have congruent arcs. Chords and Arcs. LESSON 12-2.

Download Presentation

AOX BOX by the definition of an angle bisector.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. In the diagram, radius OX bisects AOB. What can you conclude? AOXBOX by the definition of an angle bisector. AX BX because congruent central angles have congruent chords. AX BX because congruent chords have congruent arcs. Chords and Arcs LESSON 12-2 Additional Examples Quick Check

  2. Chords and Arcs LESSON 12-2 Additional Examples Find AB. QS = QR + RSSegment Addition Postulate QS = 7 + 7 Substitute. QS = 14 Simplify. AB = QSChords that are equidistant from the center of a circle are congruent. AB = 14 Substitute 14 for QS. Quick Check

  3. . . . . P and Q are points on O. The distance from O to PQ is 15 in., and PQ = 16 in. Find the radius of O. Draw a diagram to represent the situation. The distance from the center of O to PQ is measured along a perpendicular line. 1 2 PM = PQ A diameter that is perpendicular to a chord bisects the chord. 1 2 PM = (16) = 8 Substitute. The radius of O is 17 in. Chords and Arcs LESSON 12-2 Additional Examples OP2 = PM2 + OM2Use the Pythagorean Theorem. r 2 = 82 + 152Substitute. r 2 = 289 Simplify. r = 17 Find the square root of each side. Quick Check

More Related