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Light Wave Frequency and Energy Problems: Solutions Provided

This text provides solutions to problems related to the frequency and energy of light waves, including calculations for wavelength, frequency, and energy released by different light waves.

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Light Wave Frequency and Energy Problems: Solutions Provided

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  1. WAVES

  2. V=λυc=λυE=hυ *watch for nm, convert to m

  3. Review problems 1.  What is the frequency of a light wave that is 6x10-9 m long. 2. What is the frequency of a light wave that is 600 nm long? 3. How much energy is released by a light wave that has a frequency of 115 Hz? 4. The ozone molecule, O3, requires a wave of light to have a minimum of 330 nm to break each chemical bond. How much energy is needed to break apart one bond in the ozone molecule?

  4. Review problems solutions 1.  What is the frequency of a light wave that is 6x10-9 m long. f =? First, organize given information. λ = 6x10-9 m   c = 3.0 x 108 m/s c is the constant for speed of light Then plug variables into equation and solve. c= λ f 3.0 x 108 m/s = (6x10-9 m) f f = 5x1016 Hz 2. What is the frequency of a light wave that is 600 nm long? f =? First, organize given information. λ = 600nm, convert to meters 600 nm x 1 m = 6 x 10-7 m   c = 3.0 x 108 m/s 109nm c is the constant for speed of light Then plug variables into equation and solve. c= λ f 3.0 x 108 m/s = (6x10-7 m) f f = 5x1014 Hz

  5. Review problems solutions cont. 3. How much energy is released by a light wave that has a frequency of 115 Hz? f =115 Hz First, organize given information. h = planck’s constant = 6.626 x 10-34 J•s   E = ?Then plug variables into equation and solve. E= h f E = (6.626x10-34 J•s)(115 Hz) E = 7.62x10-32 J 4. The ozone molecule, O3, requires a wave of light to have a minimum of 330 nm to break each chemical bond. How much energy is needed to break apart one bond in the ozone molecule? Use c= λf to solve for f remember to convert 330 nm x 1 meter = 3.30x10-7nm the plug f into E = hf 109 nm 3.0 x 108 m/s = (3.30 x10-7 m) f f = 9.09 x1014 Hz E = (6.626x10-34J•s) (9.09 x1014 Hz) E = 6.02 x10-19 J

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