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Data Representation – Chapter 3

Data Representation – Chapter 3. Sections 3-2, 3-3, 3-4. Homework Assignment. Questions/Requests/Comments/Concerns?. Number Range. What is meant by “range”? How do you compute the range of a given set of digits?. More Representations.

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Data Representation – Chapter 3

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  1. Data Representation – Chapter 3 Sections 3-2, 3-3, 3-4

  2. Homework Assignment • Questions/Requests/Comments/Concerns?

  3. Number Range • What is meant by “range”? • How do you compute the range of a given set of digits?

  4. More Representations • Integer values are represented by a power series regardless of radix (base) 1410 = 1 x 101 + 4 x 100 11102 = 1 x 23 + 1 x 22 + 1 x 21 + 0 x 20 • What about fractions?

  5. Fraction Representations • Same principle applies 14.3710 = 1 x 101 + 4 x 100 + 3 x 10-1 + 7 x 10-2 “decimal point” 10.112 = 1 x 21 + 0 x 20 +1 x 2-1 + 1 x 2-2 “binary point”

  6. .3125 x 2 0.6250 .6250 x 2 1.2500 .2500 x 2 0.5000 .5000 x 2 1.0000 Fraction Representations • To convert a decimal fraction to binary • Multiple decimal fractional part by 2 • Output the integer part • Repeat until you’ve reached the desired accuracy 0.312510 = 0.01012

  7. Fraction Representations • More on binary floating point representations later (maybe)

  8. Addition • Decimal number addition carry 121 +19 40

  9. Addition • Binary number addition 1 111 carries 10101 +10011 101000 • It works the same way in binary as it does in decimal

  10. Subtraction • Decimal number subtraction 11 borrow 21 +19 02

  11. Subtraction • Binary number subtraction 01 borrow 10101 -10011 00010 • It works the same way in binary as it does in decimal

  12. Subtraction Questions • What about when a subtraction results in a negative value? • How do you represent a negative value in binary? • How do you represent a negative value in decimal?

  13. Negative Numbers • Decimal - 27 • Place a “-” in front of the decimal digits

  14. Negative Numbers • Binary -11011 • Place a “-” in front of the binary digits • This is called signed-magnitude representation • In the hardware the sign is a designated bit where 0 means “+” and 1 mean “–”

  15. Negative Numbers • Signed-magnitude is convenient for humans doing symbolic manipulations • It’s not convenient for computer computations • Why not? • Consider subtraction (which is really addition of a negative number)

  16. Signed-Magnitude Subtraction 21 Minuend -17 Subtrahend 4 Difference 17 Minuend -21 Subtrahend - 4 Difference

  17. Signed-Magnitude Subtraction if (M >= S) compute M-S else compute S-M place “-” on difference • To perform subtraction we must first perform a comparison! • Therein lies the inconvenience

  18. Negative Numbers Revisited • Complement representation • “(r-1)’s” complement • Given Nr , an n-digit number of radix r • “(r-1)’s” complement is (rn – 1) - Nr

  19. “(r-1)’s” complement • Decimal 1234510 n=5, r=10, N=12345 (105-1)-12345 (100000-1)-12345 99999-12345 87654 • “9’s” complement

  20. “(r-1)’s” complement • Binary 101102 n=5, r=2, N=10110 (25-1)-10110 (100000-1)-10110 11111-10110 01001 • “1’s” complement • Note that the result is just an inversion of the bits of the original number (1/0 and 0/1)

  21. “(r-1)’s” complement • So, how does this help us do subtraction? • It doesn’t really! • Furthermore the representation of 0 is ambiguous 0000 “+0” 1111 “-0” Try it!

  22. Another Complement • “r’s” complement • Given Nr , an n-digit number of radix r • “r’s” complement is “(r-1)’s” complement + 1 (rn – 1) – Nr+ 1 rn – Nr if (Nr != 0) 0 if (Nr == 0)

  23. “r’s” complement • Let’s concentrate on the 2’s complement (binary number system) • “…leaving all least significant 0’s and the first 1 unchanged, and then replacing 1’s by 0’s and 0’s by 1’s in all other higher significant bits.” • Yeah, right! • Take the “1’s” complement and add 1

  24. “2’s” Complement 101102 n=5, r=2, N=10110 (25-1)-10110 (100000-1)-10110 11111-10110 01001 1’s complement + 1 01010 2’s complement

  25. 2’s Complement “Subtraction” 0111 -0101 Original Problem 2’s Complement Problem • 0111 • +1011 • 10010 Carry Out Answer 2’s Complement

  26. 2’s Complement “Subtraction” 0101 -0111 Original Problem 2’s Complement Problem • 0101 • +1001 • 01110 Carry Out Answer 2’s Complement

  27. 2’s Complement “Subtraction” 2’s Complement Problem 2’s Complement Problem • 0111 • +1011 • 10010 • 0101 • +1001 • 01110 Carry Out Carry Out Answer 2’s Complement Answer 2’s Complement • How do we know the sign of the result?

  28. 2’s Complement “Subtraction” • Recall that we’re doing “fixed bit-length” math • When the numbers are “signed” then the most significant bit (MSB) represents the sign • MSB=1 defined as negative • MSB=0 defined as positive

  29. Sign of the Result? 2’s Complement Problem 2’s Complement Problem • 0111 • +1011 • 10010 • 0101 • +1001 • 01110 Carry Out Carry Out Answer 2’s Complement Answer 2’s Complement Sign Bit Sign Bit

  30. Sign of the Result? • The result is in 2’s complement form • If the sign bit is 1, take the 2’s complement of the result to read off the magnitude in “normal” binary notation • If the sign bit is 0, the result is in “normal” binary notation

  31. Overflow • What if the result is too big? • Remember, this is fixed bit-length math • When you add to n-bit numbers the result may be up to n+1 bits long

  32. Overflow • When a signed positive number is added to a signed (2’s complement) negative number an overflow cannot occur • The positive number magnitude will only get smaller • When two signed negative numbers or two positive numbers are added an overflow may occur • Magnitude is going to get bigger • When two signed positive numbers are added, the sign bit is treated as part of the magnitude of the number and the end carry (overflow) is not treated as “overflow”

  33. Overflow • So, when is that “extra bit” an overflow and when is it part of the result? • Check the sign bit and the overflow bit • If the two are not equal then an overflow has occurred • If the two are equal then there is no overflow

  34. Overflow • In an overflow condition • If the numbers are both positive, then the sign bit becomes part of the magnitude of the result • If the numbers are both negative, then the overflow bit is treated as the sign • As we’ll see next time (logic gates) there is a very simple way to detect overflow • Questions?

  35. “2’s” Complement • Is this cheating on the representation of 0 since we handled it with an conditional statement? • No! Try it based on the formula only! • Don’t really need to specify it as two cases • I only did it because the book did

  36. “2’s” Complement • So, how does this help us do subtraction? • Addition of a 2’s complement subtrahend. • Take 2’s complement of the subtrahend (negate the subtrahend) • Add minuend to subtrahend • Difference is in 2’s complement notation • Note we’re using a fixed, pre-specified number of bits • If the result overflows, just ignore it for now

  37. Other Binary Formats • Binary Coded Decimal (BCD) • Convert each decimal digit to its binary representation and store • Requires 4 bits per digit – why? • Forget about BCD arithmetic • Even parity/Odd parity • For a binary number, count the number of 1’s • If the number is odd, attach an extra “1” for even parity or a “0” for odd parity • If the number is even, attach an extra “0” for even parity or a “1” for odd parity • What good is this? • Gray code • Count through a sequence of binary numbers in such a way that only 1 bit at a time changes • What good is this? • American Standard Code for Information Interchange (ASCII) • Standard set of binary patterns assigned to 256 characters • How many bits comprise the ASCII code? • Unicode • Up-to-date replacement for ASCII • Various schemes utilizing various bit lengths

  38. Homework • Textbook pages 89 – 91 • 3-9, 3-10, 3-13, 3-15, 3-16, 3-17, 3-23 • Due beginning of next lecture • Begin reading Chapter 1

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