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Electricity. Unit 4: Electricity Chapter 13: Electrical Systems. 13.1 Series Circuits 13.2 Parallel Circuits 13.3 Electrical Power, AC and DC Electricity. Key Question: How can devices be connected in circuits?. 13.1 Investigation: Series Circuits. Objectives:
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Unit 4: ElectricityChapter 13: Electrical Systems • 13.1 Series Circuits • 13.2 Parallel Circuits • 13.3 Electrical Power, AC and DC Electricity
Key Question: How can devices be connected in circuits? 13.1 Investigation: Series Circuits Objectives: • Build and analyze series circuits. • Apply an understanding of Ohm’s law to explain their observations. • Describe the effects of short circuits.
Electrical Systems • In in the late 1800s, a major disagreement over the use of AC and DC electricity erupted between two famous inventors. • Thomas Edison favored the direct current (DC) method of moving electrical energy from electrical generation stations to homes and buildings. • George Westinghouse argued that the alternating current (AC) method worked better. • Which system do we use today?
Series Circuits • In a series circuit, current can only take one path, so the current is the same at all points in the circuit.
Series circuits • Inexpensive strings of holiday lights are wired with the bulbs in series. • If you remove one of the bulbs from its socket, the whole string of mini bulbs will go out.
Current and resistance in series circuits • If you know the resistance of each device, you can find the total resistance of the circuit by adding up the resistance of each device.
Current and resistance in series circuits • Adding resistances is like adding pinches to a water hose. • Each pinch adds some resistance. • Everything has some resistance, even thin wire.
Calculating current A series circuit contains a 12-V battery and three bulbs with resistances of 1 W, 2 W, and 3 W. What is the current in amps? • Looking for: …current (amps) • Given: …voltage (12V); resistances = 1Ω, 2 Ω, 3 Ω. • Relationships:Use: Rtot = R1+R2+R3and Ohm’s Law I = V ÷ R • Solution:Rtot= 6Ω and I = 12 V ÷ 6Ω = 2 amps
Energy and series circuits • The devices in a circuit convert electrical energy into other forms of energy. • Remember that the rate of energy transfer is called power, and is measured in watts (W).
Voltage drop • As devices in series use power, the power carried by the current is reduced. • As a result, the voltage is lower after each device that uses power. • This is known as the voltage drop.
Voltage drop and Ohm’s law • The law of conservation of energy also applies to a circuit. • In this circuit, each bulb has a resistance of 1 ohm, so each has a voltage drop of 1 volt when 1 amp flows through the circuit.
Kirchhoff’s Voltage Law • Kirchhoff’s voltage law states that the total of all the voltage drops must add up to the battery’s voltage.
Calculating voltage drops A circuit contains a 9-volt battery, a 1-ohm bulb, and a 2-ohm bulb. Calculate the circuit’s total resistance and current, then find each bulb’s voltage drop. • Looking for:…total resistance; and voltage drop for each bulb • Given:…voltage = 9V; resistances = 1Ω, 2 Ω. • Relationships:Rtot = R1+R2+R3 and Ohm’s Law I = V ÷ R • Solution:- part 1 Rtot= 3Ω I = 9 V ÷ 3Ω = 3 amps
Calculating voltage drop • Solution:- part 2 • Use resistance to find current: I = 9 V ÷ 3Ω = 3 amps • Solution:- part 3 • Rearrange Ohm’s law to solve for voltage. • Use current to find each voltage drop: V = I x R V1 = (3 A) x (1 Ω) = 3 volts V2 = (3 A) x (2 Ω) = 6 volts , so Rtot = (3 + 6 ) = 9 V
Unit 4: ElectricityChapter 13: Electrical Systems • 13.1 Series Circuits • 13.2 Parallel Circuits • 13.3 Electrical Power, AC and DC Electricity
Key Question: How do parallel circuits work? 13.2 Investigation: Parallel Circuits Objectives: • Build parallel circuits. • Compare and contrast series and parallel circuits. • Discuss applications of parallel circuits.
Parallel Circuits • In parallel circuits the current can take more than one path.
Kirchhoff’s Current Law • All of the current entering a branch point must exit again. • This is known as Kirchhoff’s current law.
Voltage and parallel circuits • If the voltage is the same along a wire, then the same voltage appears across each branch of a parallel circuit.
Voltage and parallel circuits • Parallel circuits have two advantages over series circuits: • Each device in the circuit has a voltage drop equal to the full battery voltage. • Each device in the circuit may be turned off independently without stopping the current in the other devices in the circuit.
Resistance in parallel circuits • Adding resistance in parallel provides another path for current, and more current flows. • When more current flows at the same voltage, the total resistance of the circuit must decrease.
Calculating resistance in parallel circuits A circuit contains a 2-ohm resistor and a 4-ohm resistor in parallel. Calculate the total resistance of the circuit. • Looking for:…the resistance • Given:…the type of circuit (parallel) and branch resistances (2 and 4 ) • Relationships:Use: the rule for parallel resistances. • Solution:
Current and parallel circuits • Each branch works independently so the total current in a parallel circuit is the sum of the currents in each branch.
Calculating in current and resistance in a parallel circuit • In a series circuit, adding an extra resistor increases the total resistance of the circuit. • In a parallel circuit, more current flows so the total resistance decreases.
Calculating current and resistance Calculate the total resistance, total current, and current in each branch for the circuit shown. • Looking for:…total resistance, total current, and each branch current. • Given: …resistance of each branch (5,1) and the total voltage (3 V) • Relationships:Use the formula for parallel resistance and Ohm’s law. • Solution:part 1 Rtot = 1/5 + 1/6 = 5/6 = 0.83
Calculating current and resistance Calculate the total resistance, total current, and current in each branch for the circuit shown. • Solution: part 2 Itot = (3 V) ÷ (0.83 ) = 3.6 A I1= (3 V) ÷ (1 ) = 3.0 A I5= (3 V) ÷ (5 ) = 0.6 A
Parallel vs. Series • Remember: series/same/current; parallel/same/voltage. • Use Ohm’s law for both.
Short circuits • A short circuit is a parallel path in a circuit with very low resistance. • A short circuit can be created accidentally by making a parallel branch with a wire.
Short circuits • Each circuit has its own fuse or circuit breaker that stops the current if it exceeds the safe amount, usually 15 or 20 amps • If you turn on too many appliances in one circuit at the same time, the circuit breaker or fuse cuts off the current. • To restore the current, you must FIRST disconnect some or all of the appliances.
Fuses • In newer homes, flip the tripped circuit breaker. • In older homes you must replace the blown fuse. • Fuses are also used in car electrical systems and in electrical devices such as televisions or in electrical meters used to test circuits.
Unit 4: ElectricityChapter 13: Electrical Systems • 13.1 Series Circuits • 13.2 Parallel Circuits • 13.3 Electrical Power, AC and DC Electricity
Key Question: How much energy is carried by electricity? 13.3 Investigation: Electrical Energy and Power Objectives: • Build parallel circuits. • Compare and contrast series and parallel circuits. • Discuss applications of parallel circuits.
Electrical Power • Electrical power is measured in watts, just like mechanical power. • Power is the rate at which energy is changed into other forms of energy such as heat, sound, or light. • Anything that “uses” electricity is actually converting electrical energy into some other type of energy.
Electrical Power • The watt is an abbreviation for one joule per second. • A 100-watt light bulb uses 100 joules of energy every second.
Power • Power is a “rate” and is measured using current and voltage.
Kilowatt • Most electrical appliances have a label that lists the power in watts (W) or kilowatts (kW). • The kilowatt is used for large amounts of power.
Calculating power A 12 V battery is connected in series to two identical light bulbs. The current in the circuit is 3 A. Calculate the power output of the battery in watts. • Looking for:... power of the battery • Given:…voltage (12 V); current (3 A) • Relationships:UsePower: P = V x I • Solution:P = (3 A)(12 V) = 36 W
Paying for Electricity • Utility companies charge customers for the number of kilowatt-hours (kWh) used each month. • A kilowatt-hour is a unit of energy. • The number of kilowatt-hours used equals the number of kilowatts multiplied by the number of hours the appliance was turned on.
Paying for Electricity • There are many simple things you can do to use less electricity. • When added up, these simple things can mean many dollars of savings each month.
Calculating cost of power How much does it cost to run a television and a video game console for 2 hours? Use the reference table and a price of $0.15 per kWh. • Looking for: …cost of T.V. + video game for 2 hours • Given: … price = $0.15/kWh, P = 250 W and 170 W; t = 2 h • Relationships:Use: no. of kWh= (price) x (t) and 1 kW = 1,000 W • Solution: 250W + 170W = 420W Convert watts to kW:420 W x 1 kW = .42 kW 1000 W No. of kWh = .42 kW x 2 h = .84 kWh Cost = .84 kWh x $ 0.15 = $0.126 = about 13¢ for 2 hours1 kWh