250 likes | 284 Views
linear pair postulate. <2. <1. Given: L intersects M <1 = 60° Prove: <2 = 120°. L. <4. <3. M. Statement Reason L intersects M given <1 = 60° given. <2. <1. L. Given: L intersects M <1 = 60° Prove: <2 = 120°. <4. <3. M. Statement Reason L intersects M given
E N D
<2 <1 Given: L intersects M <1 = 60° Prove: <2 = 120° L <4 <3 M StatementReason L intersects M given <1 = 60° given
<2 <1 L Given: L intersects M <1 = 60° Prove: <2 = 120° <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate
<2 <1 L Given: L intersects M <1 = 60° Prove: <2 = 120° <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution
<2 <1 Given: L intersects M <1 = 60° Prove: <2 = 120° L <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution <2 = 120° subtraction property
<2 <1 Given: L intersects M Prove: <1 = <3 L <4 <3 M Statement Reason L intersects M given
<2 <1 Given: L intersects M Prove: <1 = <3 L <4 <3 M Statement Reason L intersects M given <1 + <2 = 180° linear pair postulate
<2 <1 Given: L intersects M Prove: <1 = <3 L <4 <3 M Statement Reason L intersects M given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate
<2 <1 Given: L intersects M Prove: <1 = <3 L <4 <3 M Statement Reason L intersects M given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate <1 + <2 = <2 + <3 substitution
<2 <1 Given: L intersects M Prove: <1 = <3 L <4 <3 M Statement Reason L intersects M given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate <1 + <2 = <2 + <3 substitution <1 = < 3 subtraction property
<2 <1 Given: L intersects M <1 = 60° Prove: <3 = 60° L <4 <3 M Statement Reason L intersects M given <1 = 60° given
<2 <1 Given: L intersects M <1 = 60° Prove: <3 = 60° L <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate
<2 <1 Given: L intersects M <1 = 60° Prove: <3 = 60° L <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate
<2 <1 Given: L intersects M <1 = 60° Prove: <3 = 60° L <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate <1 + <2 = <2 + <3 substitution
<2 <1 Given: L intersects M <1 = 60° Prove: <3 = 60° L <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate <1 + <2 = <2 + <3 substitution <1 = < 3 subtraction property
<2 <1 Given: L intersects M <1 = 60° Prove: <3 = 60° L <4 <3 M Statement Reason L intersects M given <1 = 60° given <1 + <2 = 180° linear pair postulate <2 + <3 = 180° linear pair postulate <1 + <2 = <2 + <3 substitution <1 = < 3 subtraction property <3 = 60° substitution
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution <2 = 120 ° subtraction property
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution <2 = 120 ° subtraction property <6 = 120 ° substitution
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution <2 = 120 ° subtraction property <6 = 120 ° substitution <5 + <6 = 180° linear pair postulate
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution <2 = 120 ° subtraction property <6 = 120 ° substitution <5 + <6 = 180° linear pair postulate <5 + 120 ° = 180° substitution
<2 <1 <6 Given: <1 = 60° <2 = <6 Prove: <5 = 60° <5 <4 <3 <8 <7 Statement Reason <1 = 60° given <2 = <6 given <1 + <2 = 180° linear pair postulate 60° + <2 = 180° substitution <2 = 120 ° subtraction property <6 = 120 ° substitution <5 + <6 = 180° linear pair postulate <5 + 120 ° = 180° substitution <5 = 60° subtraction property