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18/02/2014 CH.6.5 Conditions for Special Parallelogram

18/02/2014 CH.6.5 Conditions for Special Parallelogram. Classwork. Homework. Homework Booklet Chapter: 6.5. (Pages 434 to 436 ) Exercises 1, 4, 5, 6, 9 to 16, 17, 18, 20, 22, 24 to 26, 27, 28, 33(a, b, c), 34, 39, 40, 41, 43. Warm Up Solve for x . 1. 16 x – 3 = 12 x + 13

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18/02/2014 CH.6.5 Conditions for Special Parallelogram

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  1. 18/02/2014 CH.6.5Conditions for Special Parallelogram

  2. Classwork Homework Homework Booklet Chapter: 6.5 • (Pages 434 to 436 ) Exercises 1, 4, 5, 6, 9 to 16, 17, 18, 20, 22, 24 to 26, 27, 28, 33(a, b, c), 34, 39, 40, 41, 43.

  3. Warm Up Solve for x. 1.16x – 3 = 12x + 13 2. 2x – 4 = 90 ABCD is a parallelogram. Find each measure. 3.CD4. mC 4 47 104° 14

  4. opp. s  Warm Up 1.Find AB for A (–3, 5) and B (1, 2). 2. Find the slope of JK for J(–4, 4) and K(3, –3). ABCD is a parallelogram. Justify each statement. 3.ABC  CDA 4. AEB  CED 5 –1 Vert. s Thm.

  5. Objective Prove that a given quadrilateral is a rectangle, rhombus, or square.

  6. When you are given a parallelogram with certain properties, you can use the theorems below to determine whether the parallelogram is a rectangle.

  7. A manufacture builds a mold for a desktop so that , , and mABC = 90°. Why must ABCD be a rectangle? Both pairs of opposites sides of ABCD are congruent, so ABCD is a . Since mABC = 90°, one angle ABCD is a right angle. ABCD is a rectangle by Theorem 6-5-1. Example 1: Carpentry Application

  8. Check It Out! Example 1 A carpenter’s square can be used to test that an angle is a right angle. How could the contractor use a carpenter’s square to check that the frame is a rectangle? Both pairs of opp. sides of WXYZ are , so WXYZ is a parallelogram. The contractor can use the carpenter’s square to see if one  of WXYZ is a right . If one angle is a right , then by Theorem 6-5-1 the frame is a rectangle.

  9. Below are some conditions you can use to determine whether a parallelogram is a rhombus.

  10. Caution In order to apply Theorems 6-5-1 through 6-5-5, the quadrilateral must be a parallelogram. To prove that a given quadrilateral is a square, it is sufficient to show that the figure is both a rectangle and a rhombus. You will explain why this is true in Exercise 43.

  11. Remember! You can also prove that a given quadrilateral is a rectangle, rhombus, or square by using the definitions of the special quadrilaterals.

  12. Example 2A: Applying Conditions for Special Parallelograms Determine if the conclusion is valid. If not, tell what additional information is needed to make it valid. Given: Conclusion: EFGH is a rhombus. The conclusion is not valid. By Theorem 6-5-3, if one pair of consecutive sides of a parallelogram are congruent, then the parallelogram is a rhombus. By Theorem 6-5-4, if the diagonals of a parallelogram are perpendicular, then the parallelogram is a rhombus. To apply either theorem, you must first know that ABCD is a parallelogram.

  13. Quad. with diags. bisecting each other  Example 2B: Applying Conditions for Special Parallelograms Determine if the conclusion is valid. If not, tell what additional information is needed to make it valid. Given: Conclusion: EFGH is a square. Step 1 Determine if EFGH is a parallelogram. Given EFGH is a parallelogram.

  14. with diags.   rect. with one pair of cons. sides  rhombus Example 2B Continued Step 2 Determine if EFGH is a rectangle. Given. EFGH is a rectangle. Step 3 Determine if EFGH is a rhombus. EFGH is a rhombus.

  15. Example 2B Continued Step 4 Determine is EFGH is a square. Since EFGH is a rectangle and a rhombus, it has four right angles and four congruent sides. So EFGH is a square by definition. The conclusion is valid.

  16. Check It Out! Example 2 Determine if the conclusion is valid. If not, tell what additional information is needed to make it valid. Given:ABC is a right angle. Conclusion:ABCD is a rectangle. The conclusion is not valid. By Theorem 6-5-1, if one angle of a parallelogram is a right angle, then the parallelogram is a rectangle. To apply this theorem, you need to know that ABCD is a parallelogram .

  17. Example 3A: Identifying Special Parallelograms in the Coordinate Plane Use the diagonals to determine whether a parallelogram with the given vertices is a rectangle, rhombus, or square. Give all the names that apply. P(–1, 4), Q(2, 6), R(4, 3), S(1, 1)

  18. Example 3A Continued Step 1 Graph PQRS.

  19. Since , the diagonals are congruent. PQRS is a rectangle. Example 3A Continued Step 2 Find PR and QS to determine if PQRS is a rectangle.

  20. Since , PQRS is a rhombus. Example 3A Continued Step 3 Determine if PQRS is a rhombus. Step 4 Determine if PQRS is a square. Since PQRS is a rectangle and a rhombus, it has four right angles and four congruent sides. So PQRS is a square by definition.

  21. Example 3B: Identifying Special Parallelograms in the Coordinate Plane Use the diagonals to determine whether a parallelogram with the given vertices is a rectangle, rhombus, or square. Give all the names that apply. W(0, 1), X(4, 2), Y(3, –2), Z(–1, –3) Step 1 Graph WXYZ.

  22. Since , WXYZ is not a rectangle. Example 3B Continued Step 2 Find WY and XZ to determine if WXYZ is a rectangle. Thus WXYZ is not a square.

  23. Since (–1)(1) = –1, , WXYZ is a rhombus. Example 3B Continued Step 3 Determine if WXYZ is a rhombus.

  24. Check It Out! Example 3A Use the diagonals to determine whether a parallelogram with the given vertices is a rectangle, rhombus, or square. Give all the names that apply. K(–5, –1), L(–2, 4), M(3, 1), N(0, –4)

  25. Check It Out! Example 3A Continued Step 1 Graph KLMN.

  26. Since , KMLN is a rectangle. Check It Out! Example 3A Continued Step 2 Find KM and LN to determine if KLMN is a rectangle.

  27. Check It Out! Example 3A Continued Step 3 Determine if KLMN is a rhombus. Since the product of the slopes is –1, the two lines are perpendicular. KLMN is a rhombus.

  28. Check It Out! Example 3A Continued Step 4 Determine if KLMN is a square. Since KLMN is a rectangle and a rhombus, it has four right angles and four congruent sides. So KLMN is a square by definition.

  29. Check It Out! Example 3B Use the diagonals to determine whether a parallelogram with the given vertices is a rectangle, rhombus, or square. Give all the names that apply. P(–4, 6) , Q(2, 5) , R(3, –1) , S(–3, 0)

  30. Check It Out! Example 3B Continued Step 1 Graph PQRS.

  31. Since , PQRS is not a rectangle. Thus PQRS is not a square. Check It Out! Example 3B Continued Step 2 Find PR and QS to determine if PQRS is a rectangle.

  32. Since (–1)(1) = –1, are perpendicular and congruent. PQRS is a rhombus. Check It Out! Example 3B Continued Step 3 Determine if PQRS is a rhombus.

  33. Lesson Quiz: Part I 1. Given that AB = BC = CD = DA, what additional information is needed to conclude that ABCD is a square?

  34. Lesson Quiz: Part II 2. Determine if the conclusion is valid. If not, tell what additional information is needed to make it valid. Given:PQRS and PQNM are parallelograms. Conclusion:MNRS is a rhombus. valid

  35. AC ≠ BD, so ABCD is not a rect. or a square. The slope of AC = –1, and the slope of BD = 1, so AC BD. ABCD is a rhombus. Lesson Quiz: Part III 3. Use the diagonals to determine whether a parallelogram with vertices A(2, 7), B(7, 9), C(5, 4), and D(0, 2) is a rectangle, rhombus, or square. Give all the names that apply.

  36. Objectives Prove and apply properties of rectangles, rhombuses, and squares. Use properties of rectangles, rhombuses, and squares to solve problems.

  37. Vocabulary rectangle rhombus square

  38. A second type of special quadrilateral is a rectangle. A rectangleis a quadrilateral with four right angles.

  39. Since a rectangle is a parallelogram by Theorem 6-4-1, a rectangle “inherits” all the properties of parallelograms that you learned in Lesson 6-2.

  40.  diags. bisect each other Example 1: Craft Application A woodworker constructs a rectangular picture frame so that JK = 50 cm and JL = 86 cm. Find HM. Rect.  diags.  KM = JL = 86 Def. of  segs. Substitute and simplify.

  41. Check It Out! Example 1a Carpentry The rectangular gate has diagonal braces. Find HJ. Rect.  diags.  HJ = GK = 48 Def. of  segs.

  42. Check It Out! Example 1b Carpentry The rectangular gate has diagonal braces. Find HK. Rect.  diags.  Rect.  diagonals bisect each other JL = LG Def. of  segs. JG = 2JL = 2(30.8) = 61.6 Substitute and simplify.

  43. A rhombus is another special quadrilateral. A rhombusis a quadrilateral with four congruent sides.

  44. Like a rectangle, a rhombus is a parallelogram. So you can apply the properties of parallelograms to rhombuses.

  45. Example 2A: Using Properties of Rhombuses to Find Measures TVWX is a rhombus. Find TV. WV = XT Def. of rhombus 13b – 9=3b + 4 Substitute given values. 10b =13 Subtract 3b from both sides and add 9 to both sides. b =1.3 Divide both sides by 10.

  46. Example 2A Continued TV = XT Def. of rhombus Substitute 3b + 4 for XT. TV =3b + 4 TV =3(1.3)+ 4 = 7.9 Substitute 1.3 for b and simplify.

  47. Example 2B: Using Properties of Rhombuses to Find Measures TVWX is a rhombus. Find mVTZ. mVZT =90° Rhombus  diag.  Substitute 14a + 20 for mVTZ. 14a + 20=90° Subtract 20 from both sides and divide both sides by 14. a=5

  48. Example 2B Continued Rhombus  each diag. bisects opp. s mVTZ =mZTX mVTZ =(5a – 5)° Substitute 5a – 5 for mVTZ. mVTZ =[5(5) – 5)]° = 20° Substitute 5 for a and simplify.

  49. Check It Out! Example 2a CDFG is a rhombus. Find CD. CG = GF Def. of rhombus 5a =3a + 17 Substitute a =8.5 Simplify GF = 3a + 17=42.5 Substitute CD = GF Def. of rhombus CD = 42.5 Substitute

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