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Slide 2. Directional Drilling. When is it used? Type I Wells Type II Wells Type III Wells Directional Well Planning
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1. Slide 1 PETE 661Drilling Engineering
2. Slide 2 Directional Drilling When is it used?
Type I Wells
Type II Wells
Type III Wells
Directional Well Planning & Design
Survey Calculation Methods
3. Slide 3 Read ADE Ch.8 (Reference)
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15. Slide 15 Fig. 8.11
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17. Slide 17 Azimuth
Angle
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19. Slide 19 Example 1: Design of Directional Well Design a directional well with the following restrictions:
Total horizontal departure = 4,500 ft
True vertical depth (TVD) = 12,500 ft
Depth to kickoff point (KOP) = 2,500 ft
Rate of build of hole angle = 1.5 deg/100 ft
Type I well (build and hold)
20. Slide 20 Example 1: Design of Directional Well (i) Determine the maximum hole angle required.
(ii) What is the total measured depth (MD)?
(MD = well depth measured along the wellbore,
not the vertical depth)
21. Slide 21 (i) Maximum Inclination Angle
22. Slide 22 (i) Maximum Inclination Angle
23. Slide 23 (ii) Measured Depth of Well
24. Slide 24 (ii) Measured Depth of Well
25. Slide 25 * The actual well path hardly ever coincides with the planned trajectory
* Important: Hit target within specified radius
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29. Slide 29 Wellbore Surveying Methods Average Angle
Balanced Tangential
Minimum Curvature
Radius of Curvature
Tangential
Other Topics
Kicking off from Vertical
Controlling Hole Angle
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31. Slide 31 Example - Wellbore Survey Calculations The table below gives data from a directional survey.
Survey Point Measured Depth Inclination Azimuth along the wellbore Angle Angle
ft I, deg A, deg
A 3,000 0 20
B 3,200 6 6
C 3,600 14 20
D 4,000 24 80
Based on known coordinates for point C we’ll calculate the coordinates of point D using the above information.
32. Slide 32 Example - Wellbore Survey Calculations Point C has coordinates:
x = 1,000 (ft) positive towards the east
y = 1,000 (ft) positive towards the north
z = 3,500 (ft) TVD, positive downwards
33. Slide 33 Example - Wellbore Survey Calculations I. Calculate the x, y, and z coordinates of points D using:
(i) The Average Angle method
(ii) The Balanced Tangential method
(iii) The Minimum Curvature method
(iv) The Radius of Curvature method
(v) The Tangential method
34. Slide 34 The Average Angle Method Find the coordinates of point D using the Average Angle Method
At point C, X = 1,000 ft
Y = 1,000 ft
Z = 3,500 ft
35. Slide 35 The Average Angle Method
36. Slide 36 The Average Angle Method
37. Slide 37 The Average Angle Method
38. Slide 38 The Average Angle Method
39. Slide 39 The Average Angle Method
40. Slide 40 The Average Angle Method At Point D,
X = 1,000 + 99.76 = 1,099.76 ft
Y = 1,000 + 83.71 = 1,083.71 ft
Z = 3,500 + 378.21 = 3,878.21 ft
41. Slide 41 The Balanced Tangential Method
42. Slide 42 The Balanced Tangential Method
43. Slide 43 The Balanced Tangential Method
44. Slide 44 The Balanced Tangential Method
45. Slide 45 The Balanced Tangential Method At Point D,
X = 1,000 + 96.66 = 1,096.66 ft
Y = 1,000 + 59.59 = 1,059.59 ft
Z = 3,500 + 376.77 = 3,876.77 ft
46. Slide 46 Minimum Curvature Method
47. Slide 47 Minimum Curvature Method
48. Slide 48 Minimum Curvature Method The dogleg angle, b , is given by:
49. Slide 49 Minimum Curvature Method The Ratio Factor,
50. Slide 50 Minimum Curvature Method
51. Slide 51 Minimum Curvature Method At Point D,
X = 1,000 + 97.72 = 1,097.72 ft
Y = 1,000 + 60.25 = 1,060.25 ft
Z = 3,500 + 380.91 =3,888.91 ft
52. Slide 52 The Radius of Curvature Method
53. Slide 53 The Radius of Curvature Method
54. Slide 54 The Radius of Curvature Method
55. Slide 55 The Radius of Curvature Method At Point D,
X = 1,000 + 95.14 = 1,095.14 ft
Y = 1,000 + 79.83 = 1,079.83 ft
Z = 3,500 + 377.73 = 3,877.73 ft
56. Slide 56 The Tangential Method
57. Slide 57 The Tangential Method
58. Slide 58 The Tangential Method
59. Slide 59 Summary of Results (to the nearest ft) X Y Z
Average Angle 1,100 1,084 3,878
Balanced Tangential 1,097 1,060 3,877
Minimum Curvature 1,098 1,060 3,881
Radius of Curvature 1,095 1,080 3,878
Tangential Method 1,160 1,028 3,865
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