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Valence Bond & hybridization

Valence Bond & hybridization. The orbital pattern valence electrons for 6 C are: __ __ __ __ 2s 2p x 2p y 2p z The 4 bonds in CH 4 are identical. The explanation is that valence electrons hybridize into an

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Valence Bond & hybridization

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  1. Valence Bond & hybridization The orbital pattern valence electrons for 6C are: __ __ __ __ 2s 2px 2py 2pz The 4 bonds in CH4 are identical. The explanation is that valence electrons hybridize into an sp3 hybrid: __ __ __ __ sp3 See also Molecular Shape and Orbital Hybridization (google-youtube)

  2. Valence Bond & hybridization Google-youtube: Valence bond: molecular shape and orbital hybridization. See Text page 408.

  3. Valence Bond & hybridization The bond angle for H2O is 105o. H2S bond angle is closer to normal p orbitals (90o).

  4. Valence Bond & hybridization The orbital pattern valence electrons for 8O is: __ __ __ __ 2s 2px 2py 2p H2O The 2 bonds in H2O are identical. The explanation is that valence electrons bond angles change and hybridize into an sp3 hybrid: __ __ __ __ sp3

  5. Valence Bond & hybridization The orbital pattern valence electrons for each 6C in C2H4 (sp2 hybridization) is: __ __ __ __ sp2 (σ’s) p σ See also section 7 5 sigma and pi bonds (google-youtube)

  6. Valence Bond & hybridization Draw the line bond formula Shown right in your journal. Write the molecular geometry and orbital hybridization for the following atoms in the line bond formula. 1. N 2. O 3. C in CCO 4. C in NCC 5. C in HCH 5. Locate the sigma (σ) and pi (π) bonds. Write the following bond angles: 6. _____NCC 7. _____CCO 8. _____CCC 9. _____HCH

  7. Valence Bond & hybridization Draw the molecular formula, identify the hybridized orbitals and locate the sigma and pi bonds for the following: 1. C2H2 2. CH2O 3. CH4O 4. IF4- 5. HCN6. IF2- 7. C3H6O 8. NO3- 9. C2H4O10. NO2- 11. IF4+ 12. I3-

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