90 likes | 289 Views
PYTHAGORAS THEOREM. A. 1 st side. C. B. 2 nd side. PYTHAGORAS THEOREM. In a right angled triangle the square of the hypotenuse. is equal to the sum of the squares of the other 2 sides. HYPOTENUSE. AB 2 = AC 2 + CB 2. A. C. B. PYTHAGORAS THEOREM. AB 2 = AC 2 + CB 2.
E N D
A 1st side C B 2nd side PYTHAGORAS THEOREM In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other 2 sides. HYPOTENUSE AB2 = AC2 + CB2
A C B PYTHAGORAS THEOREM AB2 = AC2 + CB2 52=32+42 25=9+16 5 cm 3 cm 4 cm
PYTHAGORAS THEOREM Problem 1: Finding the length of the hypotenuse
A Problem 1: In triangle ABC find the length of side AB. 5 cm C B 12 cm PYTHAGORAS THEOREM By Pythagoras:AB2 = AC2 + CB2 AB2 = 52 + 122 AB2 = 25 + 144 AB2 = 169 AB = AB = 13 cm
A Problem 1: In triangle ABC find the length of side AB. 5 cm C B 12 cm PYTHAGORAS THEOREM By Pythagoras:AB2 = AC2 + CB2 AB2 = 52 + 122 AB2 = 25 + 144 AB2 = 169 PROBLEM 2 RESTART AB = END SHOW AB = 13 cm
PYTHAGORAS THEOREM Problem 2: Finding the length of one of the smaller sides
P Problem 2: In triangle PQR find the length of side RQ correct to 1 d.p. 10 cm 5 cm R Q PYTHAGORAS THEOREM By Pythagoras:PQ2 = PR2 + RQ2 102 = 52 + RQ2 100 = 25 + RQ2 100 - 25 = RQ2 75 = RQ2 = RQ RQ = 8.660... cm = 8.7 cm
P Problem 2: In triangle PQR find the length of side RQ correct to 1 d.p. 10 cm 5 cm R Q PYTHAGORAS THEOREM By Pythagoras:PQ2 = PR2 + RQ2 102 = 52 + RQ2 100 = 25 + RQ2 100 - 25 = RQ2 PROBLEM 1 75 = RQ2 RESTART = RQ END SHOW RQ = 8.660... cm = 8.7 cm