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Chapter 9. Chemical Calculations I Chemical Formulas

Chapter 9. Chemical Calculations I Chemical Formulas. The Law of Definite Proportions states that in a pure compound, the elements are always present in the same definite proportion by mass. This is consistent with Atomic Theory. It allows us to make useful calculations. Chemical Formulas.

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Chapter 9. Chemical Calculations I Chemical Formulas

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  1. Chapter 9.Chemical Calculations IChemical Formulas The Law of Definite Proportions states that in a pure compound, the elements are always present in the same definite proportion by mass. This is consistent with Atomic Theory. It allows us to make useful calculations.

  2. Chemical Formulas Two samples of NH3 from different sources: # Mass of Mass of N Mass of H Sample A 1.840 g 1.513 g 0.327 g B 2.000 g 1.644 g 0.356 g A % N = 1.513 g x 100% = 82.23 % 1.840 g B % N = 1.644 g x 100% = 82.20 % 2.000 g

  3. Chemical Formulas Two samples of N2H4 from different sources: # Mass of Mass of N Mass of H Sample A 3.245 g 2.836 g 0.409 g B 2.950 g 2.578 g 0.372 g A % N = 2.836 g x 100% = 87.40 % 3.245 g B % N = 2.758 g x 100% = 87.39 % 2.950 g

  4. Chemical Formulas A property of NH3 (ammonia) is that it always has 82.2% nitrogen, regard-less of the source or amount of the sample. Hydrazine (N2H4), a different compound than ammonia, always has 87.4% nitrogen, regardless of the source or amount of the sample. Percent composition is a property of a compound.

  5. Chemical Formulas If you try to make a compound by combining its elements, you must combine them in the correct mass ratios, or you'll have some of one element left over: Make CaS (calcium sulfide) Mass Mass Mass Excess Mass Ratio of Ca of S of CaS S Ca/S 55.6 g 44.4 g 100.0 g 0.0 g 1.25/1.00 55.6 g 50.0 g 100.0 g 5.6 g 1.25/1.00

  6. Chemical Formulas What's going on? At the atomic level: 4 atoms 4 atoms 4 units of Ca of S of CaS 4 atoms 6 atoms 4 units 2 units of S of Ca of S of CaS left over

  7. Chemical Formulas And no matter what happens, the mass ratio of Ca to S in the compound is 1.25 to 1.00. Therefore, the individual atoms of Ca must be 1.25 times the mass of the S atoms. Experiments with relative masses of elements in compounds were used to determine atomic masses for the Periodic Table.

  8. Chemical Quantities How many atoms does it take to get meas-urable quantities of an element? A WHOLE LOT!!!

  9. Chemical Quantities Since we can't see or work with individual atoms, we work with them en mass, so to speak. Just like we do with lots of common things: flour, sugar, produce, other staples We also count things in groups: pairs, dozens, scores, gross, reams

  10. Moles We count atoms in groups called moles. 1.000 mole = 6.022 x 1023 atoms (atoms, or anything else)

  11. Moles

  12. Moles 1 mole = 6.022 x 1023 atoms (or anything else) This is huge! 602,200,000,000,000,000,000,000  volume of Earth's oceans in liters age of earth in seconds population of earth, individuals cost of a car, US dollars

  13. Molar Masses

  14. Molar Masses The molar mass of an element is the mass of 6.022 x 1023 atoms of that element. 1.008 g is mass of 6.022 x 1023 hydrogen atoms 12.01 g is mass of 6.022 x 1023 carbon atoms 238.0 g is mass of 6.022 x 1023 uranium atoms The atomic mass of an element is the mass of 1 atom of that element. 1.008 amu is mass of one hydrogen atom, etc.

  15. Molar Masses Relationship between grams and amu's (atomic mass units): 1.000 gram = 6.022 x 1023 amu 1.000 amu = 1.661 x 10-22 gram

  16. Molar Masses 6.022 x 1023 is also called Avogadro's number for Amedeo Avogadro, who first deduced a relationship between the number of molec-ules of a gas and its volume. Avogadro's number can be used as a conver-sion factor, like "dozen" or "score". It allows us to "count" atoms by determining the mass of a group of them.

  17. Molar Masses The molar mass is a conversion factor between moles of a substance and its mass. Molar mass has units grams g mole mol 12.01 g C 1 mol C mol C 12.01 g C

  18. Molar Masses Example: In 27.43 grams of iron, (a) How many moles of iron are there? (b) How many atoms of iron are there? Competency I-2 Note: When working with molar mass, always use enough significant figures in the molar mass to match or exceed the significant figures in other terms. Don't limit the accuracy of your work with molar mass!

  19. Molar Masses Conversion between molar mass, moles, and atoms (or molecules). Use the correct conversion, and don't use one you don't need! Molar Mass Avogadro's Number Grams Moles Atoms

  20. Molar Masses Examples: • What is the mass of 2.500 mol of carbon? (b) How many atoms of carbon are present?

  21. Molar Masses Examples: In 1.00 x 1022 atoms of gold, • What mass of gold is present? (b) How many moles of atoms are present?

  22. Molar Masses of Compounds At the atomic level, the formula of a compound gives the number of each type of atom that makes up a formula unit or molecule of the compound. At the macroscopic level, the formula of a com-pound gives the number of moles of each type of atom that makes up a mole of for-mula units or molecules of the compound.

  23. Molar Masses of Compounds One molecule of H2O contains 2 hydrogen atoms 1 oxygen atom One mole of H2O contains 2 moles of hydrogen atoms 1 mole of oxygen atoms 1 mole of water molecules

  24. Molar Masses of Compounds What is the mass of one mole of water? 2 mol H x 1.01 g H = 2.02 g H mol H 1 mol O x 16.00 g O = 16.00 g O mol O 18.02 g H2O

  25. Molar Masses of Compounds What is the mass of one mole of water? 18.02 g H2O mol H2O There are 6.022 x 1023 molecules in there, and you can swallow it in one gulp!

  26. Molar Masses of Compounds Examples: Find the molar masses of (a) N2 (b) NaCl (c) CaCO3 (d) Mg(NO3)2

  27. Percent Composition The percent composition of a compound is the percent of its mass contributed by each element in its formula. Percent composition can be calculated and checked against an experimental value to confirm the identity of a compound.

  28. Percent Composition Steps: (a) calculate molar mass of compound, writing out mass contributions of the elements (b) divide mass contribution of each element by molar mass, express result as a percentage.

  29. Percent Composition Examples: Calculate the percent composition of the following compounds. (a) H2O (b) Mg(NO3)2

  30. Empirical Formulas Empirical formulas show the smallest whole-number ratio of the elements found in a compound. One can obtain a percent composition by experiment, and use it to calculate the empirical formula of a compound. The calculation is essentially the reverse of determining a percent composition.

  31. Empirical Formulas Steps: (a) assume 100.00 g of compound, so mass percent of each element can be expressed in grams (b) calculate number of moles of each element present in that mass (c) determine mole ratios of elements (d) write empirical formula

  32. Empirical Formulas Example: The empirical formula for Freon-12, a refrigerant, is given below. De- termine its empirical formula. 9.933 % C 58.63 % Cl 31.44 % F Competency I-3

  33. Molecular Formulas Molecular formulas show the number of atoms present in a molecule of a compound. A mol-ecular formula is a whole number multiple of an empirical formula. Empirical Formula Molecular Formula NH2 N2H4 CH2 C2H4, C4H8, C6H12 CH2O C5H10O5, C6H12O6

  34. Molecular Formulas To determine a molecular formula, one needs: (a) The empirical formula of the compound. (b) The molar mass of the compound. Steps: (a) Use empirical formula to determine formula mass of compound. (b) Divide molar mass by formula mass. (c) Multiply empirical formula by result from (b)

  35. Molecular Formulas Example: Uracil, a component of ribonucleic acid (RNA), has the empirical formula C2H2NO. Its molar mass is 112.09 g/mol. What is its molecular formula? Competency I-4

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